[英]mysql where not in to left outer join
我有以下查詢,並希望將其轉換為使用左外部聯接而不是非聯接,以查看其運行速度是否會更快。 目前,此查詢大約需要40秒才能在我們的數據庫上運行。 我對使用外部聯接進行這種類型的事情以自己進行轉換還不夠熟悉。
select
c.contact_id as contact_id,
c.orgid as organization_id,
c.first_name as first_name,
c.last_name as last_name,
a.address_state as state
from cnx_contact as c
inner join cnx_address as a on c.home_address_uid = a.address_uid
where a.address_state = 'OH'
and (c.orgid = 45 or c.orgid = 55)
and c.contact_id NOT IN (
select pc.contact_id
from cnx_contact as c
inner join cnx_address as a on c.home_address_uid = a.address_uid
inner join cnx_contact_group_participant as gp on c.contact_id = gp.contact_id
inner join cnx_contact_participant_role as cr on gp.participant_role_uid = cr.participant_role_uid
inner join cnx_contact_group as cg on gp.group_uid = cg.group_uid
inner join cnx_contact_group_participant as pgp on cg.primary_participant_uid = pgp.participant_uid
inner join cnx_contact as pc on pgp.contact_id = pc.contact_id
where (c.orgid = 45 or c.orgid = 55)
and cr.name = 'Applicant'
);
select
c.columns
from cnx_contact as c
inner join cnx_address as a on c.home_address_uid = a.address_uid
LEFT JOIN
(Subquery goes here) x
ON x.contact _id = c.contact_id
where a.participant_state = 'OH'
and c.orgid IN(45,55)
and x.contact_id IS NULL;
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