分割錯誤：11，提取向量中的數據

Question

我正在嘗試用opencv和C ++編寫程序。 我有一張圖像，我試圖獲取確定的像素飽和度值，該值在（x，y）點。 我用下句話來做到這一點：

saturation_level = hsv_chanels[1].at<uchar>(x, y); 

關鍵是程序可以正常運行，但是當我嘗試運行時，它有時可以正常運行，有時會因以下錯誤而終止：

細分錯誤：11

有人知道為什么會出現此錯誤嗎？ 我讀到此錯誤是由於我的計算機內存而出現的，但我不知道為什么有時僅出現此錯誤。

編輯：

這是我尋找單應性的函數：

Mat ObtenHomografiaSuelo (vector <KeyPoint> keypoints1, vector <KeyPoint> keypoints2, Mat imagen1, Mat imagen2){
    //*****************************************************************************
    //Find homography mat
    //*****************************************************************************
    vector < Point2f > image_points[2];
    int cont = 0;

    vector<Mat> chanels_hsv1;    //[0]->H, [1]->S, [2]->V
    split( image1, chanels_hsv1 );
    vector<Mat> chanels_hsv2;
    split( image2, chanels_hsv2 );


    for(vector<KeyPoint>::const_iterator it = keypoints1.begin(); it!= keypoints1.end(); ++it){
        // Get the position of left keypoints
        float x = (it->pt.x);
        float y = (it->pt.y);

        cout << "1" << endl;
        float saturation_level = chanels_hsv1[1].at<uchar>(x, y);
        cout << "2" << endl;
        double max_level = 70.0;
        cout << "3" << endl;
        if ((y < camSize.height/4) && (saturatio_level < max_level) ){
            cout << "1:" << endl;
            waitKey (100);
            cout << "y: " << y;
            cout << "         Saturation_Level: " << nivel_saturacion << endl;
            image_points[0].push_back(Point2f(x,y));
            cout << "done" << endl;
            cont ++;
        }

    }

    cont = 0;
    for (vector<KeyPoint>::const_iterator it = keypoints2.begin(); it!=keypoints2.end(); ++it) {
        // Get the position of left keypoints
        float x = (it->pt.x);
        float y = (it->pt.y);
        float saturation_level = chanels_hsv2[1].at<uchar>(x, y);
        double max_level = 70.0;

        if ((y < (camSize.height)/4) && (saturation_level < max_level)){
            cout << "2" << endl;
            waitKey (100);
            cout << "y: " << y;
            cout << "         Saturation_Level: " << nivel_saturacion << endl;
            image_points[1].push_back(Point2f(x,y));
            cont ++;
        }
    }
    cout << "We are obtain: " << cont << " points to do the homography" << endl;
    waitKey();


    Mat H;
    H = Mat::zeros(4, 4, CV_64F);
    if (cont < 4) {
        cout << "Few points to do the homography" << endl;
    }
    else{
        if (image_points[0].size() > image_points[1].size()){
            image_points[0].resize(image_points[1].size());
        }
        else if (image_points[1].size() > image_points[0].size()){
            image_points[1].resize(image_points[0].size());
        }

        H = findHomography (image_points[0], image_points[1], CV_RANSAC, 3);
        cout << "done_matrix" << endl;

    }

    return H;
}

在調用該函數之前，我使用Harris或任何其他檢測器來檢測關鍵點，並且傳遞給該函數的圖像是由cvtColor函數轉換的HSV_image。

該錯誤出現在我之前提到的行中，因為在終端中我可以看到：

1

細分錯誤：11

Answer 1

我剛剛完成糾正錯誤，我認為這是因為我沒有有效使用函數。 我使用了兩個“ for”元素來越過我檢測到的兩個關鍵點向量，並且錯誤有時在第一時間出現，而在第二時間出現其他錯誤。 我真的不知道為什么會出錯，我只是更改代碼以更有效地進行相同的思考，然后終於可以了。

我剛剛更改了以下行：

for(vector<KeyPoint>::const_iterator it = keypoints1.begin(); it!= keypoints1.end(); ++it){
        // Get the position of left keypoints
        float x = (it->pt.x);
        float y = (it->pt.y);

        cout << "1" << endl;
        float saturation_level = chanels_hsv1[1].at<uchar>(x, y);
        cout << "2" << endl;
        double max_level = 70.0;
        cout << "3" << endl;
        if ((y < camSize.height/4) && (saturatio_level < max_level) ){
            cout << "1:" << endl;
            waitKey (100);
            cout << "y: " << y;
            cout << "         Saturation_Level: " << nivel_saturacion << endl;
            image_points[0].push_back(Point2f(x,y));
            cout << "done" << endl;
            cont ++;
        }
cont = 0;
    for (vector<KeyPoint>::const_iterator it = keypoints2.begin(); it!=keypoints2.end(); ++it) {
        // Get the position of left keypoints
        float x = (it->pt.x);
        float y = (it->pt.y);
        float saturation_level = chanels_hsv2[1].at<uchar>(x, y);
        double max_level = 70.0;

        if ((y < (camSize.height)/4) && (saturation_level < max_level)){
            cout << "2" << endl;
            waitKey (100);
            cout << "y: " << y;
            cout << "         Saturation_Level: " << nivel_saturacion << endl;
            image_points[1].push_back(Point2f(x,y));
            cont ++;
        }
    }

通過這個：

for (int i = 0; i < good_matches.size(); i++) {
        int idx1=good_matches[i].queryIdx;
        int idx2=good_matches[i].trainIdx;
        if (((keypoints[0][idx1].pt.y < (camSize.height/4)) && (canales_hsv1[1].at<uchar>(keypoints[0][idx1].pt.x, keypoints[0][idx1].pt.y) < nivel_maximo)) || ((keypoints[1][idx2].pt.y < (camSize.height/4)) && (canales_hsv2[1].at<uchar>(keypoints[1][idx1].pt.x, keypoints[1][idx2].pt.y) < nivel_maximo)) ) {
            cout << "entro" << endl;
            matched_points[0].push_back(keypoints[0][idx1].pt);
            matched_points[1].push_back(keypoints[1][idx2].pt);
            contador ++;
        }
    }

目前，我只交叉匹配的關鍵點，而不是所有關鍵點，它需要較少的計算機操作，現在可以正常工作。