[英]Countdown timer in Pygame
我開始使用 pygame,我想做簡單的游戲。 我需要的元素之一是倒數計時器。 如何在 PyGame 中進行倒計時(例如 10 秒)?
另一種簡單的方法是簡單地使用 pygame 的事件系統。
這是一個簡單的例子:
import pygame
pygame.init()
screen = pygame.display.set_mode((128, 128))
clock = pygame.time.Clock()
counter, text = 10, '10'.rjust(3)
pygame.time.set_timer(pygame.USEREVENT, 1000)
font = pygame.font.SysFont('Consolas', 30)
run = True
while run:
for e in pygame.event.get():
if e.type == pygame.USEREVENT:
counter -= 1
text = str(counter).rjust(3) if counter > 0 else 'boom!'
if e.type == pygame.QUIT:
run = False
screen.fill((255, 255, 255))
screen.blit(font.render(text, True, (0, 0, 0)), (32, 48))
pygame.display.flip()
clock.tick(60)
在此頁面上,您將找到您要查找的內容http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks
您在開始倒計時之前下載一次滴答聲(這可能是游戲中的觸發器 - 關鍵事件,無論如何)。 例如:
start_ticks=pygame.time.get_ticks() #starter tick
while mainloop: # mainloop
seconds=(pygame.time.get_ticks()-start_ticks)/1000 #calculate how many seconds
if seconds>10: # if more than 10 seconds close the game
break
print (seconds) #print how many seconds
pygame.time.Clock.tick
返回自上次clock.tick
調用( delta time , dt
)以來的時間(以毫秒為單位),因此您可以使用它來增加或減少計時器變量。
import pygame as pg
def main():
pg.init()
screen = pg.display.set_mode((640, 480))
font = pg.font.Font(None, 40)
gray = pg.Color('gray19')
blue = pg.Color('dodgerblue')
# The clock is used to limit the frame rate
# and returns the time since last tick.
clock = pg.time.Clock()
timer = 10 # Decrease this to count down.
dt = 0 # Delta time (time since last tick).
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
timer -= dt
if timer <= 0:
timer = 10 # Reset it to 10 or do something else.
screen.fill(gray)
txt = font.render(str(round(timer, 2)), True, blue)
screen.blit(txt, (70, 70))
pg.display.flip()
dt = clock.tick(30) / 1000 # / 1000 to convert to seconds.
if __name__ == '__main__':
main()
pg.quit()
在 pygame 中存在一個計時器事件。 使用pygame.time.set_timer()
重復創建USEREVENT
。 例如:
timer_interval = 500 # 0.5 seconds
timer_event = pygame.USEREVENT + 1
pygame.time.set_timer(timer_event , timer_interval)
注意,在 pygame 中可以定義客戶事件。 每個事件都需要一個唯一的 ID。 用戶事件的 id 必須在pygame.USEREVENT
(24) 和pygame.NUMEVENTS
(32) 之間。 在這種情況下, pygame.USEREVENT+1
是計時器事件的事件 ID。
要禁用事件的計時器,請將毫秒參數設置為 0。
在事件循環中接收事件:
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
elif event.type == timer_event:
# [...]
可以通過將 0 傳遞給時間參數來停止計時器事件。
看例子:
import pygame
pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 10
text = font.render(str(counter), True, (0, 128, 0))
timer_event = pygame.USEREVENT+1
pygame.time.set_timer(timer_event, 1000)
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
elif event.type == timer_event:
counter -= 1
text = font.render(str(counter), True, (0, 128, 0))
if counter == 0:
pygame.time.set_timer(timer_event, 0)
window.fill((255, 255, 255))
text_rect = text.get_rect(center = window.get_rect().center)
window.blit(text, text_rect)
pygame.display.flip()
有幾種方法可以做到這一點 - 這是一種。 據我所知,Python 沒有中斷機制。
import time, datetime
timer_stop = datetime.datetime.utcnow() +datetime.timedelta(seconds=10)
while True:
if datetime.datetime.utcnow() > timer_stop:
print "timer complete"
break
有很多方法可以做到這一點,它是其中之一
import pygame,time, sys
from pygame.locals import*
pygame.init()
screen_size = (400,400)
screen = pygame.display.set_mode(screen_size)
pygame.display.set_caption("timer")
time_left = 90 #duration of the timer in seconds
crashed = False
font = pygame.font.SysFont("Somic Sans MS", 30)
color = (255, 255, 255)
while not crashed:
for event in pygame.event.get():
if event.type == QUIT:
crashed = True
total_mins = time_left//60 # minutes left
total_sec = time_left-(60*(total_mins)) #seconds left
time_left -= 1
if time_left > -1:
text = font.render(("Time left: "+str(total_mins)+":"+str(total_sec)), True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
time.sleep(1)#making the time interval of the loop 1sec
else:
text = font.render("Time Over!!", True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
pygame.quit()
sys.exit()
另一種方法是為一個刻度設置一個新的 USEREVENT,設置它的時間間隔,然后將事件放入你的游戲循環'''
import pygame
from pygame.locals import *
import sys
pygame.init()
#just making a window to be easy to kill the program here
display = pygame.display.set_mode((300, 300))
pygame.display.set_caption("tick tock")
#set tick timer
tick = pygame.USEREVENT
pygame.time.set_timer(tick,1000)
while 1:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.USEREVENT:
if event.type == tick:
## do whatever you want when the tick happens
print('My tick happened')
這其實很簡單。 感謝 Pygame 創建了一個簡單的庫!
import pygame
x=0
while x < 10:
x+=1
pygame.time.delay(1000)
這里的所有都是它的! 玩得開心 pygame!
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.