如何使用shell腳本讀取屬性文件

Question

如何使用 shell 腳本讀取config.properties文件？

示例文件：

key1 = This is 1st value

key2 = this is 2nd value

key3

1. 顯示所有鍵和值。
2. 如何檢查哪個鍵沒有價值？
3. 輸入任何鍵相關值顯示的鍵。

Answer 1

請嘗試以下操作：

#!/bin/bash

# Read configuration into an associative array
declare -A CONFIG
# IFS is the 'internal field separator'. In this case, your file uses '='
IFS="="
while read -r key value
do
    if [ -n $value ]; then
        CONFIG[$key]=$value
    else
        CONFIG[$key]=$value
    fi
done < YOUR_CONFIG_FILENAME
unset IFS

# If a parameter is passed, look it up by that, else print everything.
if [ $1 ]; then
    if [ -n ${CONFIG[$1]} ]; then
        echo "Key: $1, Value: ${CONFIG[$1]}"
    else
        echo "The key '$1' does not exist"
    fi
else
    for key in "${!CONFIG[@]}"; do
        if [ -n ${CONFIG[$key]} ]; then
            echo "Key: $key, Value: ${CONFIG[$key]}"
        else
            echo "Key: $key has no value"
        fi
    done
fi

exit $?

它將讀取配置文件中的所有鍵名，並通知您是否未針對鍵設置任何值，以滿足您的要求（1）和（2）。

我不太了解（3）的要求

“ 3）輸入與鍵有關的值顯示的任何鍵”用該要求更新腳本。

Answer 2

你可以試試看 它也包含數據庫操作：如果您清楚地了解此代碼，則可以獲得所需的所有答案

  #!/bin/bash
    PROPERTY_FILE=filename.properties

    function getProperty {
       PROP_KEY=$1
       PROP_VALUE=`cat $PROPERTY_FILE | grep "$PROP_KEY" | cut -d'=' -f2`
       echo $PROP_VALUE
    }

    echo "# Reading property from $PROPERTY_FILE"
    DB_USER=$(getProperty "db.username")
    DB_PASS=$(getProperty "db.password")
    ROOT_LOC=$(getProperty "root.location")
    echo $DB_USER
    echo $DB_PASS
    echo $ROOT_LOC
    echo "Writing on DB ... "
    mysql -u$DB_USER -p$DB_PASS dbname<<EOFMYSQL

    update tablename set tablename.value_ = "$ROOT_LOC" where tablename.name_="Root directory location";
    EOFMYSQL
    echo "Writing root location($ROOT_LOC) is done ... "
    counter=`mysql -u${DB_USER} -p${DB_PASS} dbname -e "select count(*) from tablename where tablename.name_='Root directory location' and tablename.value_ = '$ROOT_LOC';" | grep -v "count"`;

    if [ "$counter" = "1" ]
    then
    echo "ROOT location updated"
    fi

Answer 3

這是我在項目中使用的（bash）腳本的簡化版本：

# reading CONFIG FILE
# usage: readConf <fileName> <several variable names>
function readConf {
local confFile=$1
shift
local allowedVars="$@" # only specified variable names will be processed
local forbidden=" #@%*()<>~'\"{}[]\$"

for VN in $allowedVars; do
    unset $VN
done

while IFS== read -r key val ; do
    var=${key//["$forbidden"]}
    if [[ " ${allowedVars[@]} " =~ " $var " ]]; then
    val=${val//["$forbidden"]}
    eval "${var}=\"${val}\""
    else
    if ! [ -z $var ]; then
        echo "conf parameter: \"$var\" is not supposed to be defined in \"$confFile\""
    fi
    fi
done < <(grep -v "^#" $confFile)
}

它掃描配置文件（第一個參數）以獲取指定參數（剩余參數）。 某些“禁止符號”被忽略以避免代碼注入。 以“#”開頭的行將被忽略。