如何在REST服務的RESPONSE主體中刪除Cookie

Question

在我的Java（UI和業務實施之間的中間件）項目中添加以下代碼的位置，以停止在UI中進行緩存。

Java代碼：

response.setHeader("Cache-Control", "no-cache, no-store, must-revalidate"); // HTTP 1.1.
response.setHeader("Pragma", "no-cache"); // HTTP 1.0.
response.setDateHeader("Expires", 0); // Proxies

Answer 1

通常，您會寫一個設置那些標題的過濾器。

public class NoCacheFilter implements Filter {

public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
    HttpServletRequest req = (HttpServletRequest) request;
    HttpServletResponse res = (HttpServletResponse) response;
    res.setHeader("Cache-Control", "no-cache, no-store, must-revalidate"); // HTTP 1.1.
    res.setHeader("Pragma", "no-cache"); // HTTP 1.0.
    res.setDateHeader("Expires", -1); // Proxies.

    chain.doFilter(req, res);
}


public void init(FilterConfig arg0) throws ServletException {

}

}

並將其添加到您的web.xml

<filter>
    <filter-name>NoCacheFilter </filter-name>
    <filter-class>com.example.NoCacheFilter </filter-class>
</filter>
<filter-mapping>
    <filter-name>NoCacheFilter </filter-name>
    <url-pattern>/rest/*</url-pattern>
</filter-mapping>

我已經將過濾器設置為rest URL上下文。 假設REST服務在單個上下文中。