適用於iOS的Google登錄SDK 2.0.1錯誤

Question

我正在嘗試將Google登錄集成到我的項目中，因為我正在使用“ Google登錄SDK 2.0.1”。 我已經按照developer.google網站上顯示的步驟操作，但是當我單擊按鈕時，它在- (void)signIn:(GIDSignIn *)signIn didSignInForUser:(GIDGoogleUser *)user withError:(NSError *)error返回錯誤“未知錯誤” - (void)signIn:(GIDSignIn *)signIn didSignInForUser:(GIDGoogleUser *)user withError:(NSError *)error

我已經集成了2個url方案和app-delegate，VC實現，如教程中所示

這是ViewController的代碼，其中我實現了登錄按鈕

@interface ViewController () < GIDSignInUIDelegate,GIDSignInDelegate>
@property (weak, nonatomic) IBOutlet GIDSignInButton *btnSignin;

@end

@implementation ViewController

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

- (void)viewDidLoad {
    [super viewDidLoad];
    [GIDSignIn sharedInstance].uiDelegate = self;
    [GIDSignIn sharedInstance].delegate = self;

}

// ---------------------------------------------------------------------

#pragma mark - GIDSignInDelegate

- (void)signIn:(GIDSignIn *)signIn
didSignInForUser:(GIDGoogleUser *)user
     withError:(NSError *)error {
    if (error) {
        NSLog(@"Error in signin %@",[error localizedDescription]);
        return;
    }
}

// ---------------------------------------------------------------------


- (void)signIn:(GIDSignIn *)signIn
didDisconnectWithUser:(GIDGoogleUser *)user
     withError:(NSError *)error {
    if (error) {
        NSLog(@"Error did disconnect %@",[error localizedDescription]);
        return;
    }
}

@end

Answer 1

具體的錯誤代碼是什么？ 通常，您會看到一條消息，並返回以下異常：

2015-06-18 16:36:49.463 SignInExample[20038:2727845] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Your app must support the following URL schemes: (null)'

同時需要幫助診斷的幾件事：

• 您可能想通過運行pod try Google並使用[[GGLContext sharedInstance] configureWithError: &configureError];從Google登錄快速入門開始[[GGLContext sharedInstance] configureWithError: &configureError]; 配置項目

• 如果不調用configureWithError ，則應設置客戶端ID（通常在AppDelegate中完成），例如：

  [GIDSignIn sharedInstance].clientID = "YOUR_CLIENT_ID";

• 查看Web瀏覽器地址（如果您正在模擬器中進行測試），以確保將客戶端ID傳遞到登錄流程中

• 確保將反向的客戶ID添加到您的URL方案中