簡體   English   中英

更新一個數組 php mysql

[英]Update an array php mysql

我試圖在我的數據庫中更新兩個相互依賴的數組。 我想知道是否可以使用foreach()來更新數據?

[reponse] => Array
        (
            [0] => reponse 1
            [1] => reponse 2
            [2] => reponse 3
        )

文件.php

foreach ($reponse as $key=>$value) {

  $values= mysql_real_escape_string($value);    
  $valuesch= mysql_real_escape_string($chimp[$key]);
  $query2 = mysql_query("UPDATE  reponses  SET nom_reponse=$values,id_categorie='$categorie',correct='$valuesch' where id_question='$id_question' ")  or die(mysql_error());

}

if ($query2) {

  echo "<br><div class='alert alert-info alert-dismissable'><button aria-hidden='true' data-dismiss='alert' class='close' type='button'>×</button>";
  echo "Reponse Modifer avec succes!! ";
  echo "</div> ";

} else {
  echo " Erreur  reponse!! ";
} 

我想知道這段代碼有什么問題? 以及如何正確更新它?

在谷歌並了解如何使用數組后,我找到了解決方案,要更新數據庫中的數組,我用他的鍵調用每個值,方法如下:

[reponse] => Array
        (
            [0] => reponse A
            [1] => reponse B
            [2] => reponse C
        )

    [id_reponse] => Array
        (
            [0] => 19
            [1] => 20
            [2] => 21
        )


foreach ($reponse as $key=>$value) {
        $values= mysql_real_escape_string($value);
        $valuescheck= mysql_real_escape_string($chimp[$key]);
        $valuesidr= mysql_real_escape_string($id_reponse[$key]);



        $query2 = mysql_query("UPDATE  reponses  SET nom_reponse='$values',correct='$valuescheck' where id_reponse='$valuesidr'  ")  or die(mysql_error());



            }
        if ($query2) {

            echo "<br><div class='alert alert-info alert-dismissable'><button aria-hidden='true' data-dismiss='alert' class='close' type='button'>×</button>";
            echo "Reponse Modifer avec succes!! ";
            echo "</div> ";


        } else {
            echo " Erreur  reponse!! ";
        } 

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM