共享首選項不會立即更改值嗎？

Question

我有一個GridView並且每個項目是一組打開一個活動，但首先它會檢查，如果這個項目是通過使用解鎖或不boolean ，它的值由保存SharedPreference ，如果它鎖定它改變一個String名為name的項目命名並打開AlertDialog ，如果用戶按下肯定按鈕，則應將boolean值更改為false，這意味着它不再被鎖定並且應該正常打開，但問題是不會改變，用戶必須對其進行解鎖兩次更改它，我使用Log檢查是否一切正常，除了布爾值未更改之外，其他一切都正常，有人可以告訴我如何解決此問題。

這是我的代碼：

這是我的onCreate方法：

String name;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    requestWindowFeature(Window.FEATURE_NO_TITLE);
    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN);
    setContentView(R.layout.main_menu);

    final SharedPreferences shared = getSharedPreferences("PrefName", Context.MODE_PRIVATE);
    final SharedPreferences.Editor editor = shared.edit();
    final int Coins = shared.getInt("CoinsValue", 1000);
    final boolean game = (shared.getBoolean("game", true));

    // 1. Instantiate an AlertDialog.Builder with its constructor
    AlertDialog.Builder builder = new AlertDialog.Builder(MainMenu.this);

    // 2. Chain together various setter methods to set the dialog characteristics
    builder.setMessage("Unlock a new set to have more fun")
            .setTitle("UNLOCK SET");

    // Add the buttons
    builder.setPositiveButton("100 coins", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id) {
            if (Coins >= 100){
                editor.putInt(name, false).apply();
                Toast.makeText(MainMenu.this, "Set Unlocked", Toast.LENGTH_SHORT).show();
                coinsValue = Coins - 100;
                editor.putInt("CoinsValue", coinsValue);
                editor.apply();
                Log.e("Msg", "" + name + " value = " + deathparade);
            }
        }
    });
    builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id) {
            // User cancelled the dialog
        }
    });

    // 3. Get the AlertDialog from create()
    final AlertDialog dialog = builder.create();

gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            switch (position){
                case 9:
                    Log.e("Msg", "Game value = " + game);
                    if(game){
                        name = "game";
                        editor.putString("nameLock", "game");
                        editor.apply();
                        Log.e("Msg", "" + name);
                        dialog.show();
                    } else {
                        editor.putInt("ArrayValue", R.array.game);
                        editor.putInt("DrawableValue", R.drawable.game_bg);
                        editor.apply();
                        startActivity(new Intent(MainMenu.this, MainActivity.class));
                    }
                    break;

Answer 1

使用apply()不會立即保存它。 如果需要立即保存，則應使用commit但是使用commit可能會阻塞ui線程。

注意：

如果您使用commit則會收到此警告，告訴您區別

Consider using apply() instead; commit writes its data to persistent storage immediately, whereas apply will handle it in the background