[英]How to use Dictionary in While Loop?
我正在用Python創建一個簡單的通訊錄程序。 每當我通過命令行菜單輸入多個聯系人,然后按“ b”列出所有聯系人時,它僅顯示我輸入的最后一個聯系人。 如何使程序保存所有聯系人?
# Import Collections to use Ordered Dictionary
import collections
# The main class
def main():
# Print the menu for program
print """
Contact Book App
a) New Contact
b) List Contacts
c) Search Contacts
d) Delete Contact
e) Quit
"""
# Creates an empty ordered dictionary
contact = collections.OrderedDict()
# Sets the loop as 1
loop = 1
# Create a while loop for the menu that keeps looping for user input until loop = 0
while loop == 1:
# Asks for users input from 1-5
userInput = raw_input("Please select an option: ").lower()
# OPTION 1 : ADD NEW CONTACT
if userInput == "a":
contact['name'] = raw_input("Enter name: ")
contact['phone'] = raw_input("Enter phone: ")
contact['email'] = raw_input("Enter email: ")
# Confirmation prompt
print "Contact Added!"
#For Debugging Purposes
# print(contact)
# OPTION 2 : LIST ALL CONTACTS
elif userInput == "b":
print "Listing Contacts"
print(contact)
# OPTION 3 : SEARCH CONTACTS
elif userInput == "c":
print "Searching Contacts"
print "Please Enter Contact Name"
# OPTION 4 : DELETE A CONTACT
elif userInput == "d":
print "Deleting Contact"
# OPTION 5 : QUIT PROGRAM
elif userInput == "e":
print "Quitting Contact Book"
loop = 0
else:
print "I did not understand your input"
main()
這是我的輸出:
Contact Book App
a) New Contact
b) List Contacts
c) Search Contacts
d) Delete Contact
e) Quit
Please select an option: a
Enter name: Dave Smith
Enter phone: 5553451212
Enter email: dsmith@gmail.com
Contact Added!
Please select an option: a
Enter name: John Doe
Enter phone: 4445433232
Enter email: jdoe@hotmail.com
Contact Added!
Please select an option: b
Listing Contacts
OrderedDict([('name', 'John Doe'), ('phone', '4445433232'), ('email', 'jdoe@hotmail.com')])
Please select an option:
如您所見,只有John Doe
出現,而Dave Smith
被覆蓋。
列出並添加新的聯系人:
contacts = []
...
# OPTION 1 : ADD NEW CONTACT
if userInput == "a":
contact = collections.OrderedDict()
contact['name'] = raw_input("Enter name: ")
contact['phone'] = raw_input("Enter phone: ")
contact['email'] = raw_input("Enter email: ")
contacts.append(contact)
...
contacts = []
# Sets the loop as 1
loop = 1
# Create a while loop for the menu that keeps looping for user input until loop = 0
while loop == 1:
# Asks for users input from 1-5
userInput = raw_input("Please select an option: ").lower()
# OPTION 1 : ADD NEW CONTACT
if userInput == "a":
contact = collections.OrderedDict()
contact['name'] = raw_input("Enter name: ")
contact['phone'] = raw_input("Enter phone: ")
contact['email'] = raw_input("Enter email: ")
contacts.append(contact)
# Confirmation prompt
print "Contact Added!"
#For Debugging Purposes
# print(contact)
# OPTION 2 : LIST ALL CONTACTS
elif userInput == "b":
print "Listing Contacts"
print(contacts)
[...]
每次您要求用戶提供新的聯系人詳細信息時,都會覆蓋以前創建的單個聯系人。 相反,您必須維護一個聯系人列表,創建一個新聯系人並將該聯系人添加到列表中。 另外,我建議創建一個class Contact
而不是僅僅使用字典。
class Contact:
def __init__(self, name, phone, mail):
self.name = name
self.phone = phone
self.mail = mail
def __repr__(self):
return "Contact(%r, %r, %r)" % (self.name, self.phone, self.mail)
另外,您可以使用break
退出循環,而不使用變量。 在您的main
(節選)中:
...
contacts= [] # initialize list of contacts
while True:
userInput = raw_input("Please select an option: ").lower()
if userInput == "a":
name = raw_input("Enter name: ")
phone = raw_input("Enter phone: ")
email = raw_input("Enter email: ")
contacts.append(Contact(name, phone, email)) # create and add new contact
print "Contact Added!"
elif userInput == "b":
print "Listing Contacts"
print(contacts) # use contacts list here
... more options
elif userInput == "e":
print "Quitting Contact Book"
break # use break here
else:
print "I did not understand your input"
每次您在字典中使用鍵“名稱”創建新條目時,都會覆蓋前一個。 最好創建一個新的詞典列表,並將每個人存儲為該列表中的單獨詞典。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.