[英]Make a select with one of the column based on other select and SUM
我正在使用數據庫超文件客戶端/服務器處理windev 17。
我有一個名為Operation的表,帶有colums(accountNumber,日期,金額,operationType)。
operationType可以采用兩個值:“付款”和“取款”。
我想選擇一個帳戶中完成的操作的列表,我的列表應顯示5個列:日期,帳戶編號,金額,操作類型和余額。
最后一欄(余額)應為當前日期之前“付款”類型的所有操作的總和與當前日期之前“提款”類型的所有操作的總和之差
我嘗試以下SQL代碼
SELECT date, accountNumber, operationType, deposits - withdrawals AS balance
FROM Operations o INNER JOIN (
SELECT accountNumber, date, SUM(amount) AS withdrawals
FROM Operaions
WHERE operationType = 'withdrawal'
GROUP BY accountNumber
) a ON (o.accountNumber = a.accountNumber AND a.date<=o.date)
INNER JOIN (
SELECT accountNumber,date, SUM(amount) AS deposits
FROM Operations
WHERE operationType = 'deposit'
GROUP BY accountNumber
)b ON (o.accountNumber = b.accountNumber AND b.date<=o.date)
但查詢不顯示任何值。
我也嘗試過這個
SELECT date as dateop, accountNumber, operationType, deposits - withdrawals AS balance
FROM Operations o INNER JOIN (
SELECT accountNumber, date, SUM(amount) AS withdrawals
FROM Operaions
WHERE operationType = 'withdrawal' AND date<=dateop
GROUP BY accountNumber
) a ON o.accountNumber = a.accountNumber
INNER JOIN (
SELECT accountNumber,date, SUM(amount) AS deposits
FROM Operations
WHERE operationType = 'deposit' AND date<=dateop
GROUP BY accountNumber
)b ON o.accountNumber = b.accountNumber
但是我收到一個錯誤消息,告訴我列dateop不存在。
請我需要幫助
在這里,你走我的男人。
select accountNumber, dateField, sum(isnull(deposits,0)) - sum(isnull(withdrawals,0)) from (
select accountNumber, operationType, dateField,
case when operationType = 'deposit' then sum(sum(amount)) over (partition by accountNumber, operationType order by dateField asc) else null end deposits,
case when operationType = 'withdrawal' then sum(sum(amount)) over (partition by accountNumber, operationType order by dateField asc) else null end withdrawals
from operations a
group by accountNumber, operationType, dateField
) a group by accountNumber, dateField
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