如何在Java中將十六進制字符串轉換為八進制字符串

Question

我正在將字符串轉換為十六進制字符串，我想將其轉換為八進制字符串

我正在做如下

String s="I found the reason 2 days ago i was too bussy to update you.The problem was that the UDHL was missing. I should have added 06 at the beginning.  it all works fine.For some reason I thought kannel adds this by itself (not very difficult...), but now I know it doesn't...";


String hex = String.format("%040x", new BigInteger(1, s.getBytes("UTF-8")));    

輸出是

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

我需要將十六進制轉換為八進制字符串。 我嘗試過這樣

String octal = Integer.toOctalString(Integer.parseInt(hex,16));

但是正如預期的那樣，它給了我數字格式例外，因為十六進制字符串中包含一些字符。

我想知道如何將十六進制字符串轉換為八進制字符串。

Answer 1

根據評論中的討論，您希望將每個字節分別轉換為八進制：

String s     = "My string to convert";
byte[] bytes = s.getBytes("UTF-8");

for (byte b : bytes) {
    String octalValue = Integer.toString(b, 8);

    // Do whatever
}

Answer 2

問題在於，您的輸入（ String hex ）太大了，無法存儲在單個整數中。

3個十六進制數字對應4個八進制數字。 因此，將您的輸入字符串分成三位數，使用您已經弄清楚的轉換並將輸出連接起來。