用Java解析Whatsapp日志文件

Question

我目前正在開發一個小工具，用於分析Whatsapp中群聊的用法。

我想用whatsapp日志文件來實現它。 我設法將原始.txt格式化為以下格式以使用格式化文本：

29. Jan. 12:01 - Random Name: message text
29. Jan. 12:22 - Random Name: message text
29. Jan. 12:24 - Random Name: message text
29. Jan. 12:38 - Random Name: message text
29. Jan. 12:52 - Random Name: message text

到現在為止還挺好。 問題是有一些軟線如：

29. Jan. 08:42 - Random Name2: message text 1
                 additional text of the message 1
29. Jan. 08:43 - Random Name2: message text 2

甚至更糟：

15. Jan. 14:00 - Random Name: First part of the message
                 second part
                 third part
                 forth part
                 fifth part    
29. Jan. 08:43 - Random Name2: message text 2

我想我需要一種algorythm來解決這個問題，但我在編程方面很新，不能創建這么復雜的算法。

Python中的同樣問題： 解析whatsApp會話日志

[編輯]

這是我的代碼不起作用。 （我知道這很糟糕）

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;

public class FormatList {

    public static void main(String[] args) throws IOException {
        // TODO Auto-generated method stub
        FileReader fr = new FileReader("Whatsapp_formated.txt");
        BufferedReader br = new BufferedReader(fr);

        FileWriter fw = new FileWriter("Whatsapp_formated2.txt");
        BufferedWriter ausgabe = new BufferedWriter(fw);

        String line="";
        String buffer="";

        while((line = br.readLine())!=null)
        {
            System.out.println("\n"+line);

            if(line.isEmpty())
            {

            }
            else{
                if(line.charAt(0)=='0'||line.charAt(0)=='1'||line.charAt(0)=='2'||line.charAt(0)=='3'||line.charAt(0)=='4'||line.charAt(0)=='5'||line.charAt(0)=='6'||line.charAt(0)=='7'||line.charAt(0)=='8'||line.charAt(0)=='9')
                {
                    buffer = line;

                }
                else
                {
                    buffer += line;
                }

                 ausgabe.write(buffer);
                 ausgabe.newLine();
                System.out.println(buffer);
            }

            ausgabe.close();

        }




    }

}

[編輯2]

最后我想讀出文件並分析每一行：

29. Jan. 12:01 - Random Name: message text

我可以告訴它何時發送，誰發送了它以及他寫了多少/多少

如果我現在得到以下行：

additional text of the message 1

我既不知道什么時候寫的，也不知道是誰發的

Answer 1

好吧，我相信，根據我的理解，我想出了解決問題的方案。

給定具有以下格式的文件：

29. Jan. 12:01 - Random Name: message text
29. Jan. 12:22 - Random Name: message text
29. Jan. 12:24 - Random Name: message text
29. Jan. 12:38 - Random Name: message text
29. Jan. 12:52 - Random Name: message text
29. Jan. 08:42 - Random Name2: message text 1
                 additional text of the message 1
29. Jan. 08:43 - Random Name2: message text 2
15. Jan. 14:00 - Random Name: First part of the message
                 second part
                 third part
                 forth part
                 fifth part    
29. Jan. 08:43 - Random Name2: message text 2

（這是我的“data”文件夾中名為“wsp.log”的文件。所以訪問它的路徑是“data / wsp.log”）

我期待這樣的事情：

29. Jan. 12:01 - Random Name: message text
29. Jan. 12:22 - Random Name: message text
29. Jan. 12:24 - Random Name: message text
29. Jan. 12:38 - Random Name: message text
29. Jan. 12:52 - Random Name: message text
29. Jan. 08:42 - Random Name2: message text 1 additional text of the message 1
29. Jan. 08:43 - Random Name2: message text 2
15. Jan. 14:00 - Random Name: First part of the message second part third part forth part fifth part
29. Jan. 08:43 - Random Name2: message text 2

據此，我實現了以下課程：

public class LogReader {

    public void processWspLogFile() throws IOException {
        //a. I would reference to my file
        File wspLogFile = new File("data/wsp.log");
        //b. I would use the mechanism to read the file using BufferedReader
        BufferedReader bufferedReader = new BufferedReader(new FileReader(wspLogFile));

        String currLine = null;//This is the current line (like my cursor)

        //This will hold the data of the file in String format
        StringBuilder stringFormatter = new StringBuilder();
        boolean firstIterationDone = false;//The first line will always contains the format, so I will always append it, from the second I will start making the checkings...

        // Now I can use some regex (I'm not really good at this stuff, I just used a Web Page: http://txt2re.com/)
        /* This regex will match the lines that contains the date in this format "29. Jan. 12:22", when I take a look at your file
          I can see that the "additional text of the message" does not contains any date, so I can use that as my point of separation*/
        String regex = "(\\d)(\\d)(\\.)(\\s+)([a-z])([a-z])([a-z])(\\.)(\\s+)(\\d)(\\d)(:)(\\d)(\\d)";
        //As part of using regex, I would like to create a Pattern to make the lines on the list match this expression      
        Pattern wspLogDatePattern = Pattern.compile(regex, Pattern.CASE_INSENSITIVE | Pattern.DOTALL);

        //Use of the line separator of the O.S
        String lineSeparator = System.getProperty("line.separator");

        while ((currLine = bufferedReader.readLine()) != null) {

            if (!firstIterationDone) {
                stringFormatter.append(currLine);
                firstIterationDone = true;
            } else {
                Matcher wspLogDateMatcher = wspLogDatePattern.matcher(currLine);    

                //The first time we will check if the second line has the pattern, if it does, we append a line separator
                if (wspLogDateMatcher.find()) {
                    //It is a "normal" line
                    stringFormatter.append(lineSeparator).append(currLine);             
                } else {
                    //But if it doesn't, we append it on the same line
                    stringFormatter.append(" ").append(currLine.trim());
                }
            }
        }
        System.out.println(stringFormatter.toString());
    }
}

我將以這種方式調用：

public static void main(String[] args) throws IOException {
    new LogReader().processWspLogFile();
}

希望這可以給你一些想法或對你的目的有用。 我知道需要一些改進，代碼總是需要重構:)，但到現在它可以實現預期的格式。 快樂的編碼:)。

Answer 2

試試這個代碼。 並看看它是否有意。

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;

public class WhatsappFormatted {

    public static void main(String[] args) throws IOException {
        // TODO Auto-generated method stub
        char preString = '-';
        char searchString = ':';
        FileReader fr = new FileReader("Whatsapp_formated.txt");
        BufferedReader br = new BufferedReader(fr);

        FileWriter fw = new FileWriter("Whatsapp_formated2.txt");
        BufferedWriter ausgabe = new BufferedWriter(fw);

        String line = "";
        String buffer = "";
        String lastMember = null;
        while ((line = br.readLine()) != null) {
            System.out.println("\n" + line);

            if (!line.isEmpty())

                if (Character.isDigit(line.charAt(0)) && Character.isDigit(line.charAt(1))) {
                    lastMember = line.substring(0, line.indexOf(searchString, line.indexOf(preString)) + 1);
                    buffer = line.trim();
                } else {
                    buffer += "\n" + lastMember + line.trim();
                }

            ausgabe.write(buffer);
            ausgabe.newLine();
            System.out.println(buffer);
        }

        ausgabe.close();

    }

}