[英]Setting function to call raw_input in python
我如何使這項工作? 我正在嘗試設置一個全局函數,以便我可以稍后為原始輸入調用它,而不是在需要的地方調用原始輸入。
我認為我在一定程度上掌握了我所需要的本質,但我對如何格式化它,或者是否可能進行格式化感到困惑。
先感謝您。
def choice_1():
choice_1 == raw_input("> ")
def choice_1a():
choice_1a = raw_input("> ")
def choice_1b():
choice_1b = raw_input("> ")
編輯:我認為我的問題的目的不夠清楚。 這是我正在處理的代碼的更新,也許這可以解決問題。
print "You've arrived at your desk"
def choice_1(one):
choice_1a = raw_input("< ")
def choice_1a():
choice_1a = raw_input("> ")
def choice_1b():
choice_1b = raw_input("> ")
#Choice_1
print "What do you want to do?"
print "We can \n1. Read\n2. Draw\n3. Work on homework"
print choice_1
#choice 1 branch 1
if choice_1 == "1":
print "What book should we read today?"
print "We can read\n1. Tom Sawyer\n2. Quantum Physics \n3. Ray Bradbury"
print choice_1a
if choice_1a == "1":
print "Great choice!"
if choice_1a == "2":
print "Heavy stuff there."
if choice_1a == "3":
print "Entertaining author, that one there!"
else:
print "Let's go to the library, maybe they'll have that one."
#choice 1 branch 2
if choice_1 == "2":
print "What would you like to draw?"
print "We can draw a\n1. Tiger\n2. Fish\n3. Bear "
print choice_1b
if choice_1b == "1":
print "You drew a Tiger!"
if choice_1b == "2":
print "You drew a Fish!"
if choice_1b == "3":
print "You drew a Bear!"
else:
print "Time for some improvisation."
#choice 1 branch 3
if choice_1 == "3":
print ""
這是否清除了一些混亂?
這會做你想做的。 正如@SethMMorton 所指出的,你錯過了return
def choice():
return raw_input('> ‘)
順便說一句,這不是一件好事,因為對於閱讀您的代碼的人來說,不會立即清楚choice
在做什么。
我這樣做了:
print 'Your name is :' + choice()
它按預期工作。
編輯:你應該這樣做出你的 if 語句:
if choice() == "1"
:
def multiplier(x, y):
ans = x * y
print ans
這將是一個函數的用途,當准備使用它時,你會像這樣調用它
multiplier(5, 10)
50
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