如何計算iOS中不同日期兩次的時間差？

Question

開始時間= 23:00 pm結束時間= 5:00 am

我正在嘗試這段代碼，需要從開始時間到結束時間的總和，但這對我沒有幫助

NSDateFormatter *formatter = [NSDateFormatter new];
        [formatter setDateFormat:@"HH"];

        NSDate *currentTime = [NSDate date];
        NSDate *openTime = [formatter dateFromString:start];
        NSDate *closeTime = [formatter dateFromString:end ];
        NSCalendar *calender = [NSCalendar currentCalendar];
        NSDateComponents *currentTimeComponents = [calender components:NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit fromDate:currentTime];
        NSDateComponents *openTimeComponents = [calender components:NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit fromDate:openTime];
        NSDateComponents *closeTimeComponents = [calender components:NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit fromDate:closeTime];

        NSUInteger currentTimeSeconds = currentTimeComponents.hour;

        NSUInteger openTimeSeconds = openTimeComponents.hour;

        NSUInteger closeTimeSeconds = closeTimeComponents.hour;

        if (currentTimeSeconds>openTimeSeconds && currentTimeSeconds<closeTimeSeconds) {
            NSLog(@"Time Between Open and Close Time %lu",(unsigned long)currentTimeSeconds);
        }

它顯示0小時。 請幫我一個嗎？ 提前致謝

Answer 1

如果可能的話，我將研究使用libs / frameworks通過它們的API來實現這一點。 例如，我已經使用DateTools完成了日期操作