[英]How to pass literal array as input argument of the function?
目標是在調用函數時傳遞一個常量數組(表示相應結構參數的成員變量),如{{"network", "lan"}, {"dhcp", "true"}}
作為參數:
ubus_call("router", "client", {{"network", "lan"}, {"dhcp", "true"}}, 2);
我嘗試了以下代碼,但它在編譯中返回錯誤:
struct ubus_args {
char *key;
char *val;
};
int ubus_call(char *obj, char *method, struct ubus_args u_args[], int size_args) {
printf("%s\n", obj);
printf("%s\n", method);
printf("%s %s\n", u_args->key, u_args->val);
return 0;
}
int main ()
{
ubus_call("router", "client", {{"network", "lan"}, {"dhcp", "true"}}, 2);
return 0;
}
我怎么能以正確的方式做到這一點?
這是完整的程序,你可以嘗試一下。
#include <stdio.h>
struct ubus_args {
char *key;
char *val;
};
int ubus_call(char *obj, char *method, struct ubus_args u_args[], int size_args) {
printf("%s\n", obj);
printf("%s\n", method);
printf("%s %s\n", u_args[0].key, u_args[0].val);
printf("%s %s\n", u_args[1].key, u_args[1].val);
return 0;
}
int main ()
{
ubus_call("router", "client", (struct ubus_args[2]){{"network", "lan"}, {"dhcp", "true"}}, 2);
return 0;
}
該程序在GNU GCC v4.8.3
在線編譯器上進行測試。
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