[英]How to sum up values of two dimensional array separately in PHP
問題陳述 :總結二維數組的值並單獨保存。
JSON字符串 :
{
"user_name": "USER1",
"selected_date": "07/27/2015",
"selected_project": "PROJECT1",
"tasks": [{
"task_name": " Task-1",
"work_hours": [{
"Monday": " 2"
},
{
"Tuesday": " 1"
},
{
"Wednesday": " 4"
},
{
"Thursday": " 0"
},
{
"Friday": " 0"
},
{
"Saturday": " 0"
},
{
"Sunday": " 0"
}]
},
{
"task_name": " Task-2",
"work_hours": [{
"Monday": " 5"
},
{
"Tuesday": " 1"
},
{
"Wednesday": " 5"
},
{
"Thursday": " 0"
},
{
"Friday": " 0"
},
{
"Saturday": " 0"
},
{
"Sunday": " 0"
}]
}]
}
碼
.....
$str_json = file_get_contents('php://input');
$response = json_decode($str_json, true); // decoding received JSON to array
decoded = json_decode($response, true);
$task_counter = count($decoded['tasks']);
$hour_counter = count($decoded['tasks'][0]['work_hours']);
$_tasks = array();
$_hours = array();
$_hours[] = array();
根據需要提取工作時間:
for ( $var1 = 0; $var1 <= $task_counter; $var1++)
{
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][0]['Monday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][1]['Tuesday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][2]['Wednesday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][3]['Thursday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][4]['Friday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][5]['Saturday'];
$_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][6]['Sunday'];
}
for($var = 0; $var <= $task_counter; $var++)
{
echo "|";
for ($var1 = 0; $var1 <= 7; $var1++)
{
echo $_hours[$var][$var1];
}
}
$_totalArray = array();
for ( $i=0 ; $i<=7; $i++)
{
foreach($_hours as $num => $values)
{
$_totalArray[$i] += $values[$i];
}
}
echo "<br>Task-1:$_totalArray[0]";
echo "Task-2:$_totalArray[1]";
....
預期結果:特定任務的工作時數總和。
示例 :
任務-1:7
任務-2:11
不幸的是我的邏輯出錯了。 幫助將不勝感激。
這可以做得更簡單:
$decoded = json_decode($str_json, true); // decoding received JSON to array
foreach ($decoded['tasks'] as $task) {
$total = 0;
foreach ($task['work_hours'] as $day) {
foreach ($day as $key=>$value) {
$total += $value;
}
}
echo $task['task_name'] .': ' . $total .'<br/>';
}
輸出
任務-1:7
任務-2:11
這是我的2美分(我喜歡 PHP的數組函數!):
$response = json_decode($str_json, true);
foreach($response['tasks'] as $task)
{
$workHours = [];
// flatten the $task['work_hours'] array
// this basically puts all the working hours in one array
array_walk_recursive($task['work_hours'], function ($x) use (&$workHours) { $workHours[] = $x; });
echo $task['task_name'] . ": " . array_sum($workHours);
}
試試這個 ...
$jsonObj = json_decode(
file_get_contents('test.json'),
TRUE
);
$count = array();
foreach($jsonObj['tasks'] as $task) {
$count[i] = 0;
$count[i] += $count[i] + (int)$task['work_hours']['Monday'];
$count[i] += $count[i] + (int)$task['work_hours']['Tuesday'];
$count[i] += $count[i] + (int)$task['work_hours']['Wednesday'];
$count[i] += $count[i] + (int)$task['work_hours']['Thursday'];
$count[i] += $count[i] + (int)$task['work_hours']['Friday'];
$count[i] += $count[i] + (int)$task['work_hours']['Saturday'];
$count[i] += $count[i] + (int)$task['work_hours']['Sunday'];
}
echo "Task 1 = " . $count['0'] . "\n" ."Task 2 = " . $count['1'];
這是我的解決方案(下面的一些注釋):
$data = json_decode(
file_get_contents('test.json'),
TRUE
);
//die(print_r($json));
$tasks = Array();
$work_days = Array('Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday');
foreach($data['tasks'] as $task) {
//set starting hours at 0
$tasks[$task['task_name']] = 0;
foreach($task['work_hours'] as $hours) {
foreach($work_days as $day) {
if(isset($hours[$day])) {
$tasks[$task['task_name']] += (int) $hours[$day];
}
}
}
}
print_r($tasks);
首先,你想要print_r()解碼的json - 然后查看源代碼,你將得到一個很好的視圖,如何組成數組:
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