PHP - 最簡單的方法嗎？

Question

我正在使用PDO在MySQL中檢查一個名為seasons的列，但是我如何根據它包含的內容來檢查季節和回聲的數量，例如，假設它是3，它將在一個回聲中輸出所有這些：

<a href="season 1">Season 1</a>
<a href="season 2">Season 2</a>
<a href="season 3">Season 3</a>

但是，如果它檢查其他行並且該行的季節包含5，我將需要它回應：

<a href="season 1">Season 1</a>
<a href="season 2">Season 2</a>
<a href="season 3">Season 3</a>
<a href="season 4">Season 4</a>
<a href="season 5">Season 5</a>

這一切都是在一個文件index.php中完成的，它對load的主要依賴是一個名為？name =的參數，基本上該名稱決定了要執行所有這些檢查的行。

我該怎么做？

更新：

<a href=".$dl.$dl720p1.$ref.">Season 1</a>
<a href=".$dl.$dl720p2.$ref.">Season 2</a>
<a href=".$dl.$dl720p3.$ref.">Season 3</a>
<a href=".$dl.$dl720p4.$ref.">Season 4</a>

更新：

$seasons = 1;

while (isset(${'dl720p' . $seasons})) $seasons++;

for ($i = 1; $i < $seasons; $i++)
    $download =  '<a download class="download-torrent button-green-download-big" onclick="window.open(this.href,\'_blank\');return false;" target="_blank" href="' .$dl . ${'dl720p' . $i} . $ref. '"><span class="icon-in"></span>Season ' . $i . '</a>' . "\n";

Answer 1

那么你根據有多少鏈接輸出鏈接？ 試試這個：

<?php

$dl720p1 = 'one';
$dl720p2 = 'two';
$dl720p3 = 'three';
$dl720p4 = 'four';
$dl720p5 = 'five';

$seasons = 6;

$dl = 'a';
$ref = 'b';

$download = '';

for ($i = 1; $i <= $seasons; $i++)
    $download .= '<a href="' .$dl . ${'dl720p' . $i} . $ref. '">Season ' . $i . '</a>' . "\n";

echo $download;

輸出 ：

<a href="aoneb">Season 1</a>
<a href="atwob">Season 2</a>
<a href="athreeb">Season 3</a>
<a href="afourb">Season 4</a>
<a href="afiveb">Season 5</a>