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計算mysql中文本字段中出現的多個單詞的數量

[英]Count the number of multiple words occurrences within a text field in mysql

當在Risk表的記錄ID = 1中找到business_dictionary表中的每個關鍵字時,我想對它們的出現進行計數。

business_dictionary表:

ID | Keyword
----------------
1  | manage
2  | service
3  | objectives
4  | success
5  | achieved
6  | management
7  | skills
----------------

風險表:

ID | Description
--------------------------------------------------------------------------------
1  | The quality of service has to be our first priority because the client is here to receive our service. So we have to manage all the areas supporting this service with efficiency.
--------------------------------------------------------------------------------
See results at bottom

DELIMITER $$ 

CREATE FUNCTION `getCount`(myStr VARCHAR(1000), myword VARCHAR(100)) 
RETURNS INT 

BEGIN 
DECLARE cnt INT DEFAULT 0; 
DECLARE result INT DEFAULT 1; 
WHILE (result > 0) 
DO SET result = INSTR(myStr, myword); 
IF(result > 0) THEN SET cnt = cnt + 1; 
SET myStr = SUBSTRING(myStr, result + LENGTH(myword)); 
END IF; 
END WHILE; 
RETURN cnt; 
END$$ 
DELIMITER ;

create table business_dictionary
(
    id int auto_increment primary key,
    keyword varchar(40) not null
);

insert business_dictionary (keyword) values ('manage'),('service'),('objectives'),('success'),('achieved'),('management'),('skills')

create table risk
(
    id int auto_increment primary key,
    description varchar(1000) not null
);

insert risk (description) values ('The quality of service blah blah service blah manage blah service with blah');

-- take advantage of ugly non-explicit join finally

select bd.keyword,getCount(r.description,bd.keyword) as theCount
from business_dictionary bd,risk r
where r.id=1
order by theCount desc

keyword         theCount
service         3
manage          1
skills          0
objectives      0
success         0
achieved        0
management      0

function written above shamelessly poached from:

在MySQL中計算單詞連續出現的次數

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