PHP Regex負向超前輸入

Question

我正在嘗試抓取.JSON文件，但是返回的文件在1個.json文件中返回多個JSON對象，從而導致無效的json文件。 我正在嘗試通過在JSON文件之后添加[並在JSON文件之后添加]來解決此問題。 然后使用正則表達式在正確的位置添加逗號。

這是正則表達式之前的文件

[{"status":"success"}

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

]

我創建了以下正則表達式： }(?!\\s,|\\s]) 。 我遇到的問題是，即使在最后一個}之后，它仍會添加一個，。

我得到的是：

[{"status":"success"},

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

]

預期結果：

[{"status":"success"},

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

]

Answer 1

替換\\s在您的正則表達式用\\s*由於\\s將匹配單個空格字符，其中\\s*將匹配零個或多個空格字符。

}(?!\s*[,\]])

DEMO

$re = "/}(?!\\s*[,\\]])/m";
$str = "[{\"status\":\"success\"}\n\n{\"values\":{\"cpu\":26.5152886753948387,\"ram\":0.8452846061135513},\"origin\":\"core\",\"type\":-1,\"uuid\":\"0000-e8-de-27-176d10\"}\n\n{\"values\":{\"cpu\":25.5839236550189568,\"ram\":0.8452846061135513},\"origin\":\"core\",\"type\":-1,\"uuid\":\"0000-e8-de-27-176d10\"}\n\n]";
$subst = "},";
$result = preg_replace($re, $subst, $str);