使用PowerShell將前N個文件從源目錄復制到“序列化”目標目錄

Question

Powershell或批處理腳本都將起作用。 我想將每N個文件從目錄A分發到目錄B1，B2，B3等。

示例：C：\\ a（具有9個.jpg文件）file1.jpg file2.jpg ... file9.jpg

那么c：\\ b1，C：\\ b2，C：\\ b3應該每個都有3個文件。 它也應該創建目錄C：\\ b *。

到目前為止，我想出了以下代碼，可以正常工作，但是將所有文件從目錄A復制到目錄B：

$sourceFolder = "C:\a"
$destinationFolder = "C:\b"
$maxItems = 9
Get-Childitem  $sourceFolder\*.jpg | ForEach-Object {Select-Object -First $maxItems | Robocopy $sourceFolder $destinationFolder /E /MOV}

Answer 1

這也可以，將計算應創建多少個新文件夾。

$excludealreadycopieditems = @()
$sourcefolder = "C:\a"
$destinationFolder = "C:\b"
$maxitemsinfolder = 3
#Calculate how many folders should be created:
$folderstocreate = [math]::Ceiling((get-childitem $sourcefolder\*.jpg).count / $maxitemsinfolder)
#For loop for the proces
for ($i = 1; $i -lt $folderstocreate + 1; $i++)
     {
#Create the new folders:
New-Item -ItemType directory $destinationFolder$i
#Copy the items (if moving in stead of copy use Move-Item)
get-childitem $sourcefolder\*.jpg -Exclude $excludealreadycopieditems | sort-object name | select -First $maxitemsinfolder | Copy-Item -Destination $destinationFolder$i ;
#Exclude the already copied items:
$excludealreadycopieditems = $excludealreadycopieditems + (get-childitem $destinationFolder$i\*.jpg | select -ExpandProperty name)
     }

Answer 2

這樣的事情應該做：

$cnt = 0
$i   = 1
Get-ChildItem "$sourceFolder\*.jpg" | % {
  if ($script:cnt -ge $maxItems) {
    $script:i++
    $script:cnt = 0
  }

  $dst = "$destinationFolder$script:i"
  if (-not (Test-Path -LiteralPath $dst)) {
    New-Item $dst -Type Directory | Out-Null
  }
  Copy-Item $_.FullName $dst

  $script:cnt++
}