[英]Spring MVC Login Programmatically: No qualifying bean of type MyUserDetailsService
我有一個具有Spring安全性的Spring應用程序,並且一切正常。 當我嘗試在注冊時登錄用戶時,無法正常使用...
我進行了很多搜索,發現我的委托人是我的UserDetails對象,因此我需要一個通過用戶名返回它的方法,該用戶名位於MyUserDetailsService中:
public class MyUserDetailsService implements UserDetailsService {
private UserService userService;
@Autowired(required=true)
@Qualifier(value="userService")
public void setUserService(UserService us){
this.userService = us;
}
@Override
public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException {
// Programmatic transaction management
/*
return transactionTemplate.execute(new TransactionCallback<UserDetails>() {
public UserDetails doInTransaction(TransactionStatus status) {
com.mkyong.users.model.User user = userDao.findByUserName(username);
List<GrantedAuthority> authorities = buildUserAuthority(user.getUserRole());
return buildUserForAuthentication(user, authorities);
}
});*/
Users user = userService.findByUserName(username);
List<GrantedAuthority> authorities = buildUserAuthority(user.getUserRoleses());
return buildUserForAuthentication(user, authorities);
}
// Converts com.mkyong.users.model.User user to
// org.springframework.security.core.userdetails.User
private User buildUserForAuthentication(Users user, List<GrantedAuthority> authorities) {
return new User(user.getUsername(), user.getPassword(), user.isEnabled(), true, true, true, authorities);
}
private List<GrantedAuthority> buildUserAuthority(Set<UserRoles> userRoles) {
Set<GrantedAuthority> setAuths = new HashSet<GrantedAuthority>();
// Build user's authorities
for (UserRoles userRole : userRoles) {
System.out.println("----------------------->"+userRole+"<---------------------------------------");
setAuths.add(new SimpleGrantedAuthority(userRole.getRoles().getRole() ));
}
List<GrantedAuthority> Result = new ArrayList<GrantedAuthority>(setAuths);
return Result;
}
注冊后,在我的控制器上,我嘗試通過以下方式登錄用戶:
MyUserDetailsService myuds = new MyUserDetailsService();
UserDetails ud = myuds.loadUserByUsername(user.getUsername());
// Authentication authentication = new UsernamePasswordAuthenticationToken(user.getUsername(), user.getPassword(),
// AuthorityUtils.createAuthorityList("ROLE_CONCORRENTE"));
// SecurityContextHolder.getContext().setAuthentication(authentication);
Authentication authentication = new UsernamePasswordAuthenticationToken(ud, null);
SecurityContextHolder.getContext().setAuthentication(authentication);
我什至把咖啡豆自動接線:
private MyUserDetailsService myUserDetailsService;
@Autowired(required=true)
@Qualifier(value="myUserDetailsService")
public void setMyUserDetailsService(MyUserDetailsService userdetailsservice){
this.myUserDetailsService = userdetailsservice;
}
我的豆子:
<bean id="myUserDetailsService" class="com.setelog.spring.service.MyUserDetailsService" >
<property name="userService" ref="userService" />
</bean>
在這種情況下可能會有很多問題:1)您是否已定義spring可以在其中搜索bean的包2)您是否將此類定義為服務(例如,通過使用@service注釋)3)您是否提供了其實現?
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