[英]How to retrieve out parameter from mysqli stored procedure in php?
我想使用存儲過程從mysqli數據庫訪問OUT參數,並將其保存在php變量中,以便在網頁上打印消息。
我的存儲過程是:
DELIMITER $$
CREATE procedure insertUser (IN _name varchar(50), IN _username varchar(50), IN _password varchar(50), IN _email varchar(50), IN _cellNumber int(11), IN _estateName varchar(50), OUT _rply varchar(50))
BEGIN
DECLARE count1 int;
DECLARE count2 int;
DECLARE varEstateId int;
DECLARE _result varchar(50);
select COUNT(*) into count1 from users where username = _username;
select COUNT(*) into count2 from users where email = _email;
if (count1+count2 < 1)
THEN
insert into users (username , passkey , email) VALUES (_username ,_password,_email);
insert into estatedetails (estateName, estateOwnerUsername)
values (_estateName, _username);
SELECT estateId into varEstateId from estatedetails where estateOwnerUsername = _username;
insert into usersdetail (username, name, cell1, estateId, accountType)
VALUES (_username, _name, _cellNumber, varEstateId, 'owner');
set _result = 'inserted';
else
set _result = 'alreadyExist';
end IF;
set _rply = _result;
END$$
DELIMITER;
我的用於調用存儲過程的php端代碼是:(不完整的代碼)
$db = new mysqli('localhost', 'root', '', 'estatelink');
$stmt=$db->prepare("CALL insertUser(?,?,?,?,?,?,?)");
$stmt->bind_param('ssssiss',$name, $username, $password, $email, $num, $estate_name, $rply);
$stmt->execute();
$result= $rply;
注意:我的查詢執行成功,插入數據完美。 我唯一的問題是在這種情況下如何訪問OUT參數是$ rply。
提前致謝。
您不使用輸出參數。 您可以設置其值,如下所示:
set @_rply = 'foobar';
您可以使用它,如下所示:
$db->multi_query( "CALL insertUser($name,$username,$password,$email,$cellNumber,$estateName,@_rply);SELECT @_rply as _rply" );
$db->next_result(); // flush the null RS from the call
$rs=$db->store_result(); // get the RS containing the id
echo $rs->fetch_object()->_rply, "\n";
$rs->free();
您可以在過程中使用SELECT語句,並像典型查詢一樣獲取結果
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