[英]Swift: Segue to next screen when successfully login
我在嘗試着:
1.登錄
2.解析響應
3.打印響應
4.選擇到下一個屏幕
碼
let task = session.dataTaskWithRequest(request) { (data, responseData, error) -> Void in
if let response = responseData as? NSHTTPURLResponse {
statusCode = response.statusCode
print("Response code: \(statusCode)")
}
do {
if let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .MutableLeaves) as? NSDictionary {
if let data = json["data"] as? NSDictionary {
if let user = data["user"] as? NSDictionary {
self.loggedUser = User(resp: user)
self.printData(self.loggedUser!)
}
}
}
} catch {
print(error)
err = error
}
if(statusCode != 200) {
let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
print("Error could not parse JSON: '\(jsonStr)'")
} else {
//print("Everything Looks good: \(responseData)")
self.shouldPerformSegueWithIdentifier("showHomeController", sender: self)
}
}
private func printData(user: User) {
let id = user.id as Int
print("id: \(id)")
print("Parent: \(loggedUser?.userType)")
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "showHomeController" {
let homeViewController = segue.destinationViewController as! HomeViewController
homeViewController.user = self.loggedUser
}
}
它不能以相同的順序工作。 解析數據之前,代碼正在選擇進入下一個屏幕。 為什么會這樣呢?
用performSegueWithIdentifier替換shouldPerformSegueWithIdentifier
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.