將JSON轉換為數組PHP時出錯

Question

您好，我有這個電話。

$preciobitcoin = curlCall('https://www.bitstamp.net/api/ticker/');

而且我可以完美地獲得$preciobitcoin['last'].

但是這個

$preciodolar = curlCall('https://s3.amazonaws.com/dolartoday/data.json');

作為字符串而不是數組返回

這是功能不起作用的代碼這是功能不起作用的代碼

function curlCall($url, $params = null, $contentType = 'application/json', $options = array()) {
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_FAILONERROR, true);
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, 10);
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl, CURLOPT_SSLVERSION, 4);

if (!is_null($params) && !is_null($options['key']) && !is_null($options['sig'])) {
    curl_setopt($curl, CURLOPT_POST, TRUE);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $params);
    curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: '.$contentType, 'key: '.$options['key'], 'sig: '.$options['sig']));
    //
} else if (!is_null($params) && !empty($params)) {
    curl_setopt($curl, CURLOPT_POST, TRUE);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $params);
    curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: '.$contentType));
} else {
    curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: '.$contentType));
}

// Allow for custom requests
if (isset($options['custom_request']) && !empty($options['custom_request'])) {
    curl_setopt($curl, CURLOPT_CUSTOMREQUEST, $options['custom_request']);
}

curl_setopt($curl, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; cryptoGlance ' . CURRENT_VERSION . '; PHP/' . phpversion() . ')');

$curlExec = curl_exec($curl);
if ($curlExec === false || curl_errno($curl)) {
    $data = array();
} else {
    $data = json_decode($curlExec, true);
}

if (empty($data)) {
    // return non-jsonfied data
    return $curlExec;
}

curl_close($curl);

return $data;

}

Answer 1

可能是編碼問題。 這是一個可以在我的本地主機上正常工作的示例。

$str = file_get_contents( 'https://s3.amazonaws.com/dolartoday/data.json' );
var_dump( mb_detect_encoding( $str ) );

$str = mb_convert_encoding( $str, "UTF-8" );
var_dump( mb_detect_encoding( $str ) );

var_dump( json_decode( $str ));

Answer 2

快速調用json_last_error（）會返回此

格式錯誤的UTF-8字符，可能編碼錯誤

該文件中可能有一些隱藏的壞字符（不是utf8）。