如何使用JavaScript從URL抓取任何句段？

Question

我有一個網址： http://localhost:8080/school/teacher/reports/chapter-quiz/student

在最后一段，我只需要這樣做

var lastSegment = location.pathname.split('/').pop();

但是，如何抓住最后一個旁邊的一個呢？ 章知多少

Answer 1

我會說這樣的話？

var segments      = location.pathname.split('/');
secondLastSegment = segments[segments.length - 2];

Answer 2

分割細分

var pathArray = window.location.pathname.split( '/' );

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創建變量

• var segment_1 = pathArray[1];
• var segment_2 = pathArray[2];
• var segment_3 = pathArray[3];
• var segment_4 = pathArray[4];

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用它

console.log(segment_4) --> chapter-quiz

Answer 3

你可以用這個

var t = window.location.pathname.split("/")
t.pop();
t.pop();
t.pop();

Answer 4

此函數將返回路徑的特定部分，從末尾開始計數。
pathFromEnd(url, 0)返回最后一部分， pathFromEnd(url, 1)返回倒數第二部分，依此類推...它了解url語法：有/無協議，尾部斜杠，參數...

 function pathFromEnd(url, pos) { return url.match(new RegExp("^(?:.*?:\\\\/\\\\/)?[^\\\\/]*(?:\\\\/([^\\\\/?]*))*?(?:\\\\/[^\\\\/?]*){" + pos + "}\\\\/?(?:\\\\?.*)?$"))[1]; } alert(pathFromEnd("http://localhost:8080/school/teacher/reports/chapter-quiz/student", 1)); alert(pathFromEnd("localhost:8080/school/teacher/reports/chapter-quiz/student/", 1)); alert(pathFromEnd("www.example.com/school/teacher/reports/chapter-quiz/student?a=b", 1));