SQL獲取電話號碼序列

Question

我有一個名為PhoneNumbers的表，其中包含Phone和Range列，如下所示

在“電話”列中，我有一個電話號碼，在“范圍”列中，我有一個值范圍，我需要包含這些電話號碼。對於第一個電話號碼9125678463，我需要包含電話號碼，直到范圍9125678465，即（9125678463， 9125678464,9125678465）。同樣也適用於其他電話號碼。此處的示例目標表應類似於

我怎么寫SQL來得到這個？

提前致謝

Answer 1

您可以像這樣使用CTE：

;WITH CTE (PhoneNumbers, [Range], i) AS (
    SELECT CAST(Phone AS bigint), [Range], CAST(1 AS bigint)
    FROM yourTable
    UNION ALL
    SELECT CAST(PhoneNumbers + 1 AS bigint), [Range], i + 1
    FROM CTE
    WHERE (PhoneNumbers + 1) % 10000 <= [Range] 
)
SELECT PhoneNumbers
FROM CTE
ORDER BY PhoneNumbers

Answer 2

這是使用理貨表格的一個示例。 在我的系統中，我將這套ctes作為視圖，因此不必再編寫它。

if OBJECT_ID('tempdb..#PhoneNumbers') is not null
    drop table #PhoneNumbers;

create table #PhoneNumbers
(
    Phone char(10)
    , Range smallint
) 

insert #PhoneNumbers
    select 9135678463, 8465 union all
    select 3279275678, 5679 union all
    select 6372938103, 8105;

WITH
E1(N) AS (select 1 from (values (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))dt(n)),
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS 
(
    SELECT  ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
)

select *
from #PhoneNumbers p
join cteTally t on t.N >= RIGHT(Phone, 4) and t.N <= Range
order by p.Phone

Answer 3

我有一個解決方案，但采用了經典的方式：但是它不需要遞歸，也不需要任何循環！ 即使您的范圍長度為3或5，或任何其他值，它也能正常工作...

首先，我創建一個帶有數字的表（在此示例中為1到1百萬-您可以在TOP（）子句中采用此表）：

SELECT TOP (1000000) n = CONVERT(INT, ROW_NUMBER() OVER (ORDER BY s1.[object_id]))
INTO dbo.Numbers
FROM sys.all_objects AS s1 CROSS JOIN sys.all_objects AS s2
OPTION (MAXDOP 1);

CREATE UNIQUE CLUSTERED INDEX idx_numbers ON dbo.Numbers(n)
;

如果您有該表，則非常簡單：

;WITH phonenumbers
AS
(
SELECT  phone,
        [range],
        CAST(RIGHT(phone,LEN([range])) AS INT) AS number_to_increase,
        CAST(LEFT(phone,LEN(phone)-LEN([range])) + REPLICATE('0',LEN([range])) AS BIGINT) AS base_number
FROM    PhoneNumbers
)

SELECT  p.base_number + num.n
FROM    phonenumbers p
        INNER JOIN dbo.Numbers num ON num.n BETWEEN p.number_to_increase AND p.[range]

您不必像在這里那樣使用CTE-只是更清楚地了解這種方法的思想是什么。 也許這適合你

Answer 4

另一種方法：

--Creating dummy table
select '9999991234' phone, '1237' rang into #tbl
union
select '9999995689', '5692'

SELECT [phone] low
        ,(CAST(9999995689/10000 AS bigINT) * 10000  + [Rang]) high
 into #tbl1
 FROM #tbl

--Creating 'numbrs' to have numbers between 0 & 9999 i.e. max range

select (rn-1)rn
into #numbrs
from 
(select row_number() over (partition by null order by A.object_id) rn from sys.objects A 
cross join sys.objects B)A 
where rn between 0 and 9999

select (low + rn)phn from #numbrs cross join #tbl1
where (low + rn) between low and high