[英]Sorting/Filtering JSON based on certain property
所以我從API得到了這個響應。 我想從所有類型構建一個選擇框,如何在不使用循環的情況下僅從此JSON中提取與skill_level相關的JSON。
[
{
"id": 32,
"name": "Beginner",
"type": "skill_level"
},
{
"id": 33,
"name": "Intermediate",
"type": "skill_level"
},
{
"id": 34,
"name": "Experienced",
"type": "skill_level"
},
{
"id": 35,
"name": "Professional",
"type": "skill_level"
},
{
"id": 36,
"name": "Expert",
"type": "skill_level"
},
{
"id": 37,
"name": "Male",
"type": "sex"
},
{
"id": 38,
"name": "Female",
"type": "sex"
},
{
"id": 39,
"name": "Single",
"type": "marital_status"
},
{
"id": 40,
"name": "Married",
"type": "marital_status"
},
{
"id": 41,
"name": "Divorced",
"type": "marital_status"
},
{
"id": 42,
"name": "Not Wish To Say",
"type": "marital_status"
}
]
Array.prototype.filter
出Array.prototype.filter
:
var skillLevels = data.filter(function(item) {
return item.type === 'skill_level';
});
從文檔來看,這如下:
filter()方法創建一個新數組,其中所有元素都通過了由提供的函數實現的測試。
假設data
是指你在你的問題中提供的陣列,這將導致與skillLevels
是包含所有在項目的新的陣列item.type
等於"skill_level"
。
我剛剛發現您也可以在AngularJs中這樣做:
<select id="sex" name="sex" ng-model="sex">
<option ng-repeat="option in $scope.data | filter:{type: 'sex'}" value="{{option.id}}">{{option.name}}</option>
</select>
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