[英]Python Script not running from django shell
我正在從Django Shell運行Python腳本。 在我添加main()
函數之前,它一直工作良好。 現在不起作用。 當我執行腳本時,什么也沒有發生(沒有錯誤或任何東西)。 我究竟做錯了什么?
在Django Shell中,我像這樣執行腳本: execfile('create_xml.py')
create_xml.py:
import os
import unicodedata
from django.conf import settings
from django.template.loader import render_to_string
from databank.models import Registration
def create_xml(registrations):
for registration in registrations:
xml = render_to_string('databank/metadata.xml', {'registration': registration})
filename = "metadata%s.xml" % (registration.dataset.dataset_id)
file_path = settings.XML_DATA_FILES
with open(os.path.join(file_path, filename), 'w') as f:
f.write(xml.encode('UTF-8'))
def main():
while True:
print "For which datasets would you like to create XML files?"
dsid = input("1: All datasets\t2: Public datasets only\t3: A specific dataset- ")
if ds == 1:
# all datasets
print "Creating XML files for all datasets."
registrations = Registration.objects.all()
create_xml(registrations)
print "All done!"
elif ds == 2:
# only public datasets
print "Creating XML files for public datasets only."
registrations = Registration.objects.filter(dataset__status='public')
create_xml(registrations)
print "All done!"
elif ds == 3:
dsid = input("Please input a dataset id: ")
try:
r = Registration.objects.get(dataset__dataset_id=dsid)
print "Creating XML file for dataset %d." % (dsid)
registrations = [r]
create_xml(registrations)
print "All done!"
except:
print "Not a valid dataset id. please try again."
else:
print "Not a valid option."
if __name__ == "__main__":
main()
發生這種情況是因為__name__ == '__main__'
僅在python解釋器將文件作為程序運行時才為True
。 嘗試在程序中打印__name__
,然后在更改比較后執行execfile()
。 您將找出__name__
變量。 檢查__name__ ==“ __main__”怎么辦?
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