如何使用Selenium Python單擊Canvas中的Element

Question

我試圖單擊第一個canvas元素，但是沒有點擊。 我嘗試通過以下方式：

第一種方式

menu = driver.find_element_by_xpath("*//div[@id = 'cy']/div/canvas")
ActionChains(driver).move_to_element(menu).perform()

第二路

driver.find_element_by_xpath("*//div[@id = 'cy']/div/canvas").click()

這是html代碼：

<div id="cy">
<div style="position: absolute; z-index: 0; overflow: hidden; width: 1029px; height: 130px;">
<canvas style="position: absolute; z-index: 5; width: 1029px; height: 130px;" data-id="layer0-selectbox" width="1029" height="130"></canvas>
<canvas style="position: absolute; z-index: 4; width: 1029px; height: 130px;" data-id="layer1" width="1029" height="130"></canvas>
<canvas style="position: absolute; z-index: 3; width: 1029px; height: 130px;" data-id="layer2-drag" width="1029" height="130"></canvas>
<canvas style="position: absolute; z-index: 2; width: 1029px; height: 130px;" data-id="layer3" width="1029" height="130"></canvas>
<canvas style="position: absolute; z-index: 1; width: 1029px; height: 130px;" data-id="layer4-node" width="1029" height="130"></canvas>
</div>
</div>

Answer 1

嘗試move_to_element_with_offset ，它應該為您工作：

http://selenium.googlecode.com/svn/trunk/docs/api/py/_modules/selenium/webdriver/common/action_chains.html#ActionChains.move_to_element_with_offset