無法弄清楚這個簡單的JS代碼出了什么問題
[英]Can't figure out what's wrong with this simple JS code
問題描述
標題是不言自明的，我有這個JS代碼（回到基礎知識）非常簡單，但是我無法終生弄清楚為什么我不運行。 我所知道的是開發人員控制台在第21行說了意外的令牌“ {”，但這就是打開我的if語句的原因。
enter code here
<!Doctype html>
<html land="en">
<head>
<meta charset="utf-8" />
<title>Chapter 2, Example 7</title>
</head>
<body>
<script type="text/javascript">
var myAge = parseInt(prompt ("Enter your age", 30),10);
if (myAge >= 0 && myAge <= 100) {
document.write("myAge is between 0 and 10<br />");
}
if (!(myAge >= 0 && myAge <= 10) ) {
document.write("myAge is NOT between 0 and 10<br />");
}
if (myAge >= 80 || myAge <= 10) {
document.write("myAge is 80 or above OR 10 or below<br />");
}
if ( (myAge >= 30 && myAge <= 39 || (myAge >= 80 && myAge <= 89) ) {
document.write("myAge is between 30 and 39 or myAge is " +
"is between 80 and 89");
}
</script>
</body>
</html>
2 個解決方案
解決方案1
2 2015-07-30 17:37:49
您在此行上缺少括號
if ((myAge >= 30 && myAge <= 39 || (myAge >= 80 && myAge <= 89)) {
應該
if ((myAge >= 30 && myAge <= 39) || (myAge >= 80 && myAge <= 89)) {
解決方案2
0 2015-07-30 17:39:19
更改
if ( (myAge >= 30 && myAge <= 39 || (myAge >= 80 && myAge <= 89) ) {
至
if ( (myAge >= 30 && myAge <= 39) || (myAge >= 80 && myAge <= 89) ) {
或者，如果您願意，可以使用關鍵字運算符優先級 ：
if (myAge >= 30 && myAge <= 39 || myAge >= 80 && myAge <= 89) {
和一點提示
if (myAge >= 0 && myAge <= 100) { // <-- or this should be 10 ...?
document.write("myAge is between 0 and 10<br />");
} // ^^
// should be 100?
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