java.lang.ArithmeticException：無終止的十進制擴展

Question

if (builderAggregateCalculationsType == AggregateCalculationsType.AGGREGATE_AVERAGE) {
            BigDecimal quarterDivisor = new BigDecimal(3);
            quarterDivisor = quarterDivisor.setScale(
                    aggregateCalculationsNumberOfDecimalPlaces,
                    RoundingMode.HALF_UP);
            firstQuarterSum = firstQuarterSum.setScale(
                    aggregateCalculationsNumberOfDecimalPlaces,
                    RoundingMode.HALF_UP);
            secondQuarterSum = secondQuarterSum.setScale(
                    aggregateCalculationsNumberOfDecimalPlaces,
                    RoundingMode.HALF_UP);

            firstQuarterSum = firstQuarterSum.divide(quarterDivisor);
            secondQuarterSum = secondQuarterSum.divide(quarterDivisor);

        }

Answer 1

問題在於，除法結果產生的Non-terminating分數。 1/3東西會產生0.3333....不會終止。

如果可以允許某些錯誤，則可以指定RoundingMode並使用它，

firstQuarterSum.divide(quarterDivisor, RoundingMode.HALF_UP); // Or any other rounding mode you prefer.