來自數據庫的json_decode多維

Question

我將此json保存在數據庫中名為“價格”且類型為“文本”的列中。

{
  "desks": {
    "Dedicated Desk": "$400 mo"
  },
  "private offices": {
    "1 Person": "$550 mo",
    "2 Person": "$1100 mo",
    "3 Person": "$1600 mo",
    "4 Person": "$2100 mo",
    "6 Person": "$3300 mo"
  },
  "flexible membership": {
    "Starting at": "$45 mo",
    "Every Extra Day": "$50 Day"
  }
}

然后，我從PHP進行調用以返回數據庫中的所有字段並將它們編碼為json。

$json = json_encode($response,JSON_PRETTY_PRINT);
echo $json;

$ response是來自數據庫的響應。 當我在$ response上進行var_dump時，我得到了

array(22) {
    [0]=>
      object(stdClass)#6 (38) {
        [...]

        ["price"]=>
        string(242) "{"desks":{"Dedicated Desk":"$400 mo"},"private offices":{"1 Person":"$550 mo","2 Person":"$1100 mo","3 Person":"$1600 mo","4 Person":"$2100 mo","6 Person":"$3300 mo"},"flexible membership":{"Starting at":"$45 mo","Every Extra Day":"$50 Day"}}"

        [...]
      }
    [...]
}

當我從json_encode回顯結果時，我得到

[
    {
        [...]

        "price": "{\"desks\":{\"Dedicated Desk\":\"$400 mo\"},\"private offices\":{\"1 Person\":\"$550 mo\",\"2 Person\":\"$1100 mo\",\"3 Person\":\"$1600 mo\",\"4 Person\":\"$2100 mo\",\"6 Person\":\"$3300 mo\"},\"flexible membership\":{\"Starting at\":\"$45 mo\",\"Every Extra Day\":\"$50 Day\"}}",

        [...]
    },
    [...]
]

我的問題是json_encode從數據庫獲取json並將其格式化為字符串。 我正在嘗試將其格式化為多維json結構的一部分。 這是我試圖實現的目標：

[  
   {  
      "price":[  
         {  
            "desks":{  
               "Dedicated Desk":"$400 mo"
            },
            "private offices":{  
               "1 Person":"$550 mo",
               "2 Person":"$1100 mo",
               "3 Person":"$1600 mo",
               "4 Person":"$2100 mo",
               "6 Person":"$3300 mo"
            },
            "flexible membership":{  
               "Starting at":"$45 mo",
               "Every Extra Day":"$50 Day"
            }
         }
      ]
   }
]

任何幫助，將不勝感激。 運行最新版本的php。

Answer 1

它將其編碼為字符串，因為它是字符串。 您需要做的是首先對其進行解碼。

 $response['price'] = json_decode($response['price']);
 $json = json_encode($response,JSON_PRETTY_PRINT);
 echo $json;