從table1刪除，其中column1大於table2.column1乘以2

Question

如您所見，標題非常好。

嘗試刪除其中一個列的值是另一張表的兩倍的行。

select DB
delete 
from table1
where table1.id IN (select table2.id where table1.price > table2.price*2)

我想查詢相匹配的id column ，並刪除所有table1是有一個行table1.column1兩倍大的對口table2.column1 。 我應該使用什么語法？

Answer 1

您需要在子查詢中聯接表。 下面的示例假設兩個表都有一個唯一的名為“ id”的id列

delete 
from table1
where table1.id IN (
select table2.id from table1, table2 where 
table1.id = table2.id
and
table1.price > (table2.price*2))

Answer 2

從刪除table1匹配id和條件price在table1比更大的table2

DELETE FROM table1
FROM   table1 INNER JOIN ON
table1 .id = table2.id
WHERE  (table1 .price  > table2.price* 2)

Answer 3

如果兩個表可以通過其id連接，則只需執行以下操作：

select DB
delete 
from table1
where table1.id IN (
  select table2.id from table1 inner join table2 on table2.id=table1.id
  where table1.price > table2.price*2)

Answer 4

delete from table1 where id in 
(select id from table1 join table2 on table1.id = table2.id
where table1.column1 > 2*table2.column1)