[英]how to get data from database in laravel with json?
如果正在laravel 5中接收過電子郵件,我想在ajax中進行驗證。
這是我的ajax:
$.ajax({
type: 'POST',
url: '/EditEmail',
data: form.serialize(),
dataType: 'json',
timeout: 9000,
error:function(data) {
//verify if the user has already been taken
},
success:function(data) {
window.location.href=window.location.href;
}
});
這是我的控制器中的代碼:
public function EditEmail()
{
if(Hash::check(Input::get('ParolaActuala'),$parola) && count(User::where('email','=',$NoulEmail)->get()) == 0 )
{
DB::table('users')->where ('user_id',Auth::user()->user_id)->update(array('email' => Input::get('NoulEmail')));
return Response::json(['success' => 'request succeeded'], 200);
}
}
所以我已經在控制器中進行了驗證,並且用戶無法引入同一封電子郵件,但是我想知道如何將數據從控制器發送到ajax,以便我也可以在其中進行驗證。有人有解決方案嗎?
您有兩個選擇。
使用statusCode的第一個選項:
根據Ajax文檔( http://api.jquery.com/jQuery.ajax/ ),您可以執行以下操作:
statusCode: {
200: function() {
alert( "user found" );
},
404: function() {
alert( "user not found" );
}
}
並在您的控制器中返回:
// user does not exist
return Response::json(['status' => 'not_found'], 404);
//or if the user does exist
return Response::json(['status' => 'found'], 200);
使用簡單json數據的第二個選擇:
$.ajax({
type: 'POST',
url: '/EditEmail',
data: form.serialize(),
dataType: 'json',
timeout: 9000,
error:function(data) {
//something went wrong with the request
},
success:function(data) {
if(data['status'] == "found") {
alert( "user found" );
} else {
alert( "user not found" );
}
}
});
並在您的控制器中:
public function EditEmail()
{
if(Hash::check(Input::get('ParolaActuala'),$parola) && count(User::where('email','=',$NoulEmail)->get()) == 0 )
{
DB::table('users')->where ('user_id',Auth::user()->user_id)->update(array('email' => Input::get('NoulEmail')));
return Response::json(['status' => 'not_found']);
}
return Response::json(['status' => 'found']);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.