[英]Java code not running as planned
這不是整個代碼,只是問題所在。 (下面的完整代碼)
if (passLength > 4) {
System.out.println("Signup alost complete.");
Random rand = new Random();
int randm = rand.nextInt(100000) + 1;
System.out.println(
"To confirm you are not a robot, please enter this code: "
+ randm);
String code = userInput.next();
if (code.equals(randm)) {
System.out.println("Thank you, " + userName);
System.out.println(
"You may now login. Begin by entering your username");
if (userInput.equals(userName)) {
System.out.println("Now please enter you password");
}
// Where the rest of the program will go
}
else {
System.out.println("The code entered is incorrect.");
}
}
else {
System.out.println("Invalid Password");
}
我正在制作一個程序,用戶在該程序中創建一個帳戶,然后登錄。我遇到的問題是驗證,以確保用戶是人(顯然是,但仍然)。 創建他們的用戶名和密碼后,我生成並打印一個隨機int,他們必須將其鍵入回來。
我的問題是程序總是跳到else
語句,並顯示"The code entered is incorrect."
即使我輸入完美。
誰能告訴我我在做什么錯?
下面是完整的代碼,以防萬一。
public static void main(String[] args) {
System.out.println("Hi! To begin please choose your username.");
System.out.println("To do this, please enter your username below. ");
System.out.println("This name must be at least three characters.");
Scanner userInput = new Scanner(System.in);
String userName = userInput.next();
int nameLength = userName.length();
if (nameLength > 2) {
System.out.println("Now please enter your password.");
System.out
.println("This password must be at lease five characters");
String passWord = userInput.next();
int passLength = passWord.length();
if (passLength > 4) {
System.out.println("Signup alost complete.");
Random rand = new Random();
int randm = rand.nextInt(100000) + 1;
System.out.println(
"To confirm you are not a robot, please enter this code: "
+ randm);
String code = userInput.next();
if (code.equals(randm)) {
System.out.println("Thank you, " + userName);
System.out.println(
"You may now login. Begin by entering your username");
if (userInput.equals(userName)) {
System.out.println("Now please enter you password");
}
// Where the rest of the program will go
}
else {
System.out.println("The code entered is incorrect.");
}
}
else {
System.out.println("Invalid Password");
}
}
else {
System.out.println("Invalid Username");
}
}
您正在將String與整數進行比較,這顯然不能相同。
int randm = rand.nextInt(100000) + 1;
...
String code = userInput.next();
if (code.equals(randm))
要解決該問題,您可以將整數轉換為String並比較字符串(或以其他方式)。
String randm = String.valueOfrand.nextInt(100000) + 1;
...
String code = userInput.next();
if (code.equals(randm)) // Comparing string now
編輯:正如@Pshemo指出的那樣, int code = userInput.nextInt();
假設您將整數與==
進行比較,它將完成工作。
這是因為randm是int而代碼是String。 因此,代碼if (code.equals(randm))
總是結果為false。
您不能比較字符串和整數。 嘗試將輸入作為整數而不是字符串。 String code = userInput.next();
而是使用:
int code= userInput.nextInt();
if(code==randm)
或者您也可以將整數轉換為字符串
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