顯示數據庫結果

Question

我在顯示數據庫中的記錄時遇到一個問題，因為我使用中間表。 但我將嘗試解釋。 我的數據庫中有下一個表：

• 類型 （ id，naam ）
• 商店 （ id，naam，type_id ……不重要）
• 產品 （ id，naam ，...不重要）
• product_shop_tt （ id，product_id，shop_id ）-那是我在產品商店之間的中間表
• 訂單 （ id，user_id，狀態 ）
• order_details （ id，order_id，user_id，product_shop_tt_id ）
• 用戶 （ id，naam，不重要 ）

現在我有下一個代碼：

<?php

$rezKor = mysqli_query($kon, "SELECT * FROM korisnici WHERE email = '". $_COOKIE["korisnik"] ."' LIMIT 1");
$redKor = mysqli_fetch_assoc($rezKor);
$user_id =  $redKor["id"];

$rezOrders = mysqli_query($kon, "SELECT * FROM orders WHERE user_id = ". $user_id ." AND status = 0 ORDER BY id DESC LIMIT 1");
$redOrders = mysqli_fetch_assoc($rezOrders);
$brRez = mysqli_num_rows($rezOrders);

$rezOrdDetails = mysqli_query($kon, "SELECT * FROM order_details WHERE order_id = ". $redOrders["id"] ."");

while($redOrdDetails = mysqli_fetch_assoc($rezOrdDetails)){
    $rezTT = mysqli_query($kon, "SELECT * FROM product_shop_tt WHERE id = ". $redOrdDetails["product_shop_tt_id"] ."");
    $redTT = mysqli_fetch_assoc($rezTT);
    $brTT = mysqli_num_rows($rezTT);

    $i = 0;
    $rezShop = mysqli_query($kon, "SELECT * FROM shops WHERE id = ". $redTT["shop_id"] ."");
    while($redShop = mysqli_fetch_assoc($rezShop)){
        if($i == 0){
            echo $redShop["naam"] . "<br />";
        }
        $i++;
        $rezProdukt = mysqli_query($kon, "SELECT * FROM producten WHERE id = ". $redTT["product_id"] ."");
        while($redProduct = mysqli_fetch_assoc($rezProdukt)){
            echo "<br />Ime produkta : " . $redProduct["naam"] . "<br />";
        }
    }
}

echo "<div style=\"clear:both;\"></div><div class=\"footer\" style=\"position: fixed;bottom: 0;width: 100%;left:0;\">
    <a href=\"home.php\" title=\"Ga terug\" class=\"col-xs-6 col-sm-6 btn btn-info\"><span class=\"glyphicon glyphicon-chevron-left\"></span> Niets toevoegen</a>
    <button class=\"col-xs-6 col-sm-6 btn btn-danger\" type=\"submit\" name=\"btnNaruci\" id=\"btnNaruci\">
        Leg in winkelmand <span class=\"glyphicon glyphicon-chevron-right\"></span><span class=\"glyphicon glyphicon-chevron-right\"></span><span class=\"glyphicon glyphicon-chevron-right\"></span>
    </button>
</div>";

?>

我想獲得下一個輸出：

 <h1>Type of the shops</h1><br /> <h3>The name of the first shop</h3> <ul> <li>Product from the first shop</li> <li>Product from the first shop</li> </ul><br /> <h3>The name of the second shop</h3> <ul> <li>Product from the second shop</li> <li>Product from the second shop</li> </ul><br /><br /> <h1>Type of the shops</h1><br /> <h3>The name of the next shop</h3> <ul> <li>Product from shop</li> <li>Product from shop</li> </ul><br /> <h3>The name of the new shop</h3> <ul> <li>Product from the new shop</li> <li>Product from the new shop</li> </ul> 

但是用我的代碼我得到下一個：

 <div>Type of the shops</div> <div>The name of the first shop</div> <div>Product from the first shop</div><br /> <div>Type of the shops</div> <div>The name of the first shop</div> <div>Product from the first shop</div><br /> <div>Type of the shops</div> <div>The name of the first shop</div> <div>Product from the first shop</div><br /> 

因此，我想顯示同一家商店下面所有產品的名稱。 現在，我為每種產品獲得商店名稱和商店類型。

我希望我能很好地解釋。

在此先感謝您的幫助。

Answer 1

感謝@Sean。

<?php

    $rezOrders = mysqli_query($kon, "SELECT * FROM orders WHERE user_id = ". $user_id ." AND status = 0 ORDER BY id DESC LIMIT 1");
    $redOrders = mysqli_fetch_assoc($rezOrders);


    $rez = mysqli_query($kon, "SELECT product_shop_tt.*, shops.*, shops.naam as shopNaam, producten.*, producten.naam as prodNaam, order_details.*, type.*, type.naam as typeNaam 
                                FROM order_details INNER JOIN product_shop_tt ON order_details.product_shop_tt_id = product_shop_tt.id
                                INNER JOIN shops ON shops.id = product_shop_tt.shop_id
                                INNER JOIN producten ON producten.id = product_shop_tt.product_id 
                                INNER JOIN type ON type.id = shops.type_id 
                                WHERE order_id = ". $redOrders["id"] ."");

    $currentType = "";
    $currentShop = "";
    while($red = mysqli_fetch_assoc($rez)){
        if ($red["typeNaam"] != $currentType){
                echo "Type : " . $red["typeNaam"] . "<br />";
                $currentType = $red["typeNaam"];
            }
        if ($red["shopNaam"] != $currentShop){
                echo "Shop : " . $red["shopNaam"] . "<br />";
                $currentShop = $red["shopNaam"];
            }
                echo "Product : " . $red["prodNaam"] . "<br />"; 
        }
?>

這是執行我所需要的代碼。

非常感謝@Sean！ 干杯