如何通過ajax將Django模型查詢集發送到模板？

Question

假設我有模型Abc和標簽，它們之間有很多關系，

    options = Abc.objects.all()
    tagsset = []
    for entry in options:
        tags_arr = entry.tags_set.all()
    if tags_arr:
        tagsset.append(tags_arr)



     data = {}

如何格式化數據中的查詢集和選項集？

Answer 1

您可以將它們放入字典中，將其轉換為json，然后它們返回json_object

data = {}
data['options'] = options
data['tagsset'] = tagsset

json_object = json.dumps(data)

return HttpResponse(json_object)

上面的代碼將json對象發送到調用的ajax方法

Answer 2

簡單答案：

data = {}
data['options'] = options
data['tagset'] = tagset
# NOTE: since you skip empty tag sets,
#       len(tagset) <= len(options)
# so if you are going to match tagsets with options in the
# browser, they may not match length-wise

盡管該問題僅詢問格式化返回參數的問題，但此答案顯示了執行此操作的另一種方法（對於要打包和發送更多數據的情況，這是更好的IMO。此方法還將相關數據保持在一起，即選項和相關標簽綁定在一起。

# payload is the data to be sent to the browser
payload = []
# get all options and associated tags
# this will be a list of tuples, where each tuple will be
# option, list[tags]
for option in Abc.objects.all():
    payload.append((
        option,  # the option
        list(option.tags_set.all()),  # list of linked tags
    ))
# return this payload to browser
return HttpResponse(
        # good practice to name your data parameters
        json.dumps({ 'data': payload, }),
        # always set content type -> good practice!
        content_type='application/json'
    )


# in the browser template, you can do something such as:
{% for option, tags in data %}
    {{ option.something }}
    {% for tag in tags %}
        {{ tag.something }}
    {% endfor %}
{% endfor %}