[英]Comparing a pointer to a pointer with a character?
我有一個字符數組。 指針指向該字符數組。 同樣,另一個指針指向該指針,即它是指向指針的指針。 現在,我需要將指針與帶有字符文字的指針進行比較,例如“ a”。
我嘗試了strcmp,但是沒有用。
我怎樣才能做到這一點?
char arr[1000];
char *ptr,*ptr1,**curr;
ptr=arr; //pointer pointer to that array
curr=&ptr; //pointer to a pointer
if(**curr=='.') //doesn't work
printf("Some code");
如果我理解正確,那么您在談論以下內容
#include <string.h>
//...
char arr[1000] = "a";
char *ptr = arr;
char **curr = &ptr;
if ( strcmp( *curr, "a" ) == 0 ) puts( "They are equal" );
要么
#include <string.h>
//...
char arr[1000] = "abcd";
char *ptr = arr;
char **curr = &ptr;
char *ptr2 = "ab";
if ( strncmp( *curr, ptr2, strlen( ptr2 ) ) == 0 ) puts( "They are equal" );
如果您需要比較單個字符,則可以編寫
char arr[1000] = "a";
char *ptr = arr;
char **curr = &ptr;
if ( **curr == 'a' ) puts( "They are equal" );
要么
char arr[1000] = "ab";
char *ptr = arr;
char **curr = &ptr;
if ( ( *curr )[1] == 'b' ) puts( "They are equal" );
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