Angular-加載所有JS后的調用函數

Question

我要在加載所有文件（JS）時調用一個函數（因為我想調用其中一個文件內的函數）。 我怎么做？

     .state('dashboard', {
         url: "/dashboard.html",
         templateUrl: "views/dashboard.html",            
         data: {pageTitle: 'Dashboard'},
         controller: "DashboardController",
         resolve: {
             deps: ['$ocLazyLoad', function($ocLazyLoad) {
                 return $ocLazyLoad.load({
                     name: 'MetronicApp',
                     insertBefore: '#ng_load_plugins_before', 
                     files: [
                         '/assets/global/plugins/morris/morris.css',
                         '/assets/admin/pages/css/tasks.css',

                         '/assets/global/plugins/morris/morris.min.js',
                         '/assets/global/plugins/morris/raphael-min.js',
                         '/assets/global/plugins/jquery.sparkline.min.js',

                         '/assets/admin/pages/scripts/index3.js',
                         '/assets/admin/pages/scripts/tasks.js', 
                         //'/js_custom/dashboard.js', 

                         'js/controllers/DashboardController.js'
                     ] 
                 });
             }]
         }
     })

來源：Metronic模板AngularJS版本

Answer 1

看起來$ocLazyLoad.load()返回了一個$ocLazyLoad.load() 。 加載完所有文件后，應解決此問題。 文檔中有一個類似於您想要的示例：

[...]
return $ocLazyLoad.load('js/ServiceTest.js').then(function() {
  var $serviceTest = $injector.get("$serviceTest");
  $serviceTest.doSomething();
});