[英]Grep from a file and output pattern if not found
我有一個文件ids_list.csv
,其中包含一個ID列表,每行一個。
我還有一個日志文件,我想在其中找到ids_list.txt
的id。
我想要的是將日志文件中的行(如果找到該模式)打印到result.txt
文件,否則將其打印。
所以我寫了這個腳本:
#!/bin/bash
for i in `cat ids_list.csv`;
do
echo $i
echo `grep $i log_FVAScope`
if [[ ! res=$(grep $i log_FVAScope) ]]; then
echo $i >> result.txt;
else
echo $res >> result.txt
fi
done
但是, result.txt
為空,我在做什么錯?
而且它似乎很慢,我如何加快速度( ids_list.csv
包含約40k行,日志文件包含70萬行)?
編輯:樣本輸入:
ids_list.csv
:
KBKEQO17564
SPXTCT769178
KBKFXS1952894
CDNEVL_4148105
BBR10000130794156
日志文件 :
18:51:59.368 [pool-1-thread-4] INFO c.s.m.x.liqor.filter.CodChainFilter - KBKEQO17564 excluded by CodeChain Filter
18:51:59.369 [pool-1-thread-5] INFO c.s.m.x.liqor.filter.CodChainFilter - KBKFXS1952894 excluded by CodeChain Filter
18:51:59.369 [main] INFO c.s.m.x.l.manager.FilterManagerImpl - waiting new deals to submit
18:51:59.369 [pool-1-thread-2] INFO c.s.m.x.liqor.filter.CodChainFilter - CDNEVL_4148105 excluded by CodeChain Filter
18:51:59.369 [pool-1-thread-1] INFO c.s.m.x.liqor.filter.CodChainFilter - BBR10000130794156 excluded by CodeChain Filter
所需的輸出( result.txt
) :
18:51:59.368 [pool-1-thread-4] INFO c.s.m.x.liqor.filter.CodChainFilter - KBKEQO17564 excluded by CodeChain Filter
SPXTCT769178
18:51:59.369 [pool-1-thread-5] INFO c.s.m.x.liqor.filter.CodChainFilter - KBKFXS1952894 excluded by CodeChain Filter
18:51:59.369 [main] INFO c.s.m.x.l.manager.FilterManagerImpl - waiting new deals to submit
18:51:59.369 [pool-1-thread-2] INFO c.s.m.x.liqor.filter.CodChainFilter - CDNEVL_4148105 excluded by CodeChain Filter
18:51:59.369 [pool-1-thread-1] INFO c.s.m.x.liqor.filter.CodChainFilter - BBR10000130794156 excluded by CodeChain Filter
好吧,您實際上不需要腳本。 下面的命令可以滿足您的需求。
while read line; do grep $line log_FVAScope >> result.txt ; done < ids_list.csv
我不知道性能問題。
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