[英]AJAX request saves to database but alerts failed
我有一個引導模式聯系表單,該表單使用AJAX和PHP將用戶發送的信息保存到數據庫:
<div class="modal fade" id="contact" role="dialogue">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-body">
<form id="myform" role="form">
<div class="form-group">
<label for="name">Name: </label>
<input type="name" name="name" class="form-control" id="name" >
</div>
<div class="form-group">
<label for="email">Email: </label>
<input type="email" name="email" class="form-control" id="email">
</div>
<div class="form-group">
<label for="msg">Message: </label>
<textarea class="form-control" name="msg" id="msg" rows="10"></textarea>
</div>
<!-- <a class="btn btn-primary" data-dismiss="modal">Close</a> -->
<button id="sub" type="submit" name="submit" class="btn btn-default">Submit</button>
</form>
</div>
</div>
</div>
</div>
當我提交表單時,頁面會警告AJAX請求失敗,但是信息仍然保存到數據庫中! 任何人都知道我要去哪里錯了,我在下面附加了我的script.js和send.php文件:
Javascript / Ajax文件:
$(document).ready(function(){
$('#myform').submit(function(){
$.ajax({
type: 'post',
url: 'send.php',
dataType: 'json',
async: true,
data: $('#myform').serialize(),
success: function(msg){
alert("It was a success");
return false;
},
error: function(jqXHR, textStatus, errorThrown){
alert("Fail");
console.log(jqXHR + '-' + textStatus + '-' + errorThrown);
return false;
}
});
});
});
PHP文件,用於處理並保存到數據庫
<?php
include 'connect.php';
if(isset($_POST['name'])&&($_POST['email'])&&($_POST['msg']))
{
$sql = "INSERT INTO details (name, email, message) VALUES (:Name, :Email, :Msg)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':Name', $_POST['name'], PDO::PARAM_STR);
$stmt->bindParam(':Email', $_POST['email'], PDO::PARAM_STR);
$stmt->bindParam(':Msg', $_POST['msg'], PDO::PARAM_STR);
$stmt->execute();
echo "done";
}else{
echo "Nothing posted";
}
?>
PS沒有錯誤輸出到控制台,只是警報說失敗。
根據您的JavaScript,您的Ajax期望收到json結果,請看此行
dataType: 'json',
但是在您的php代碼中,您僅在回顯字符串
echo "Nothing posted";
兩個解決方案,請在您的javascript dataType中刪除此代碼:'json'或在您的php中返回一個json
$data['result'] = "nothing posted";
echo json_encode($data);
正如Luis所建議的,嘗試將適當的標頭添加到php文件中,該標頭將保存到數據庫中,並使輸出json對象如下所示:
<?php
include 'connect.php';
//The json header
header('Content-type: application/json');
header("Content-Disposition: inline; filename=ajax.json");
if(isset($_POST['name'])&&($_POST['email'])&&($_POST['msg']))
{
$sql = "INSERT INTO details (name, email, message) VALUES (:Name, :Email, :Msg)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':Name', $_POST['name'], PDO::PARAM_STR);
$stmt->bindParam(':Email', $_POST['email'], PDO::PARAM_STR);
$stmt->bindParam(':Msg', $_POST['msg'], PDO::PARAM_STR);
$stmt->execute();
$result = array('success'=>true, 'message'=>'The data has been saved successfuly');
} else {
$result = array('success'=>false, 'message'=>'Can\'t save the data');
}
//Also is a good practice to omit the php closing tag in order to prevent empty characters which could break the posted headers
echo json_encode($result);
我將使用以下別名代替$ .ajax,但這是個人喜好:
$(document).ready(function(){
$('#myform').submit(function(e){
e.preventDefault(); //Prevent form submission, so the page doesn't refresh
$.post('send.php', $(this).serialize(), function(response){
console.log(response); //see what is in the response in the dev console
if(response.success == true){
//success action
//...some code here...
} else {
//error action, display the message
alert(response.message);
}
});
});
});
希望能有所幫助
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