關於如何計算每個帖子的評論數量的SQL查詢

Question

我有兩個名為“評論”和“帖子”的數據庫表

在“posts”表中我得到了post_id，post_title

在“評論”表中，我收到了comment_id，post_id，message

評論表中的post_id存儲正在評論的帖子的ID。 通過這種方式，我可以計算一篇文章的評論數量。

我嘗試做研究並最終得到以下代碼：

$displaypost = "SELECT * FROM posts";
$result = $conn->query($displaypost);

if ($result->num_rows > 0) {

    while($row = $result->fetch_assoc()) {
        $postid = $row['post_id'];
        $posttitle =$row['post_title'];

        $countdata = "SELECT COUNT(post_id) FROM comments WHERE post_id='$postid'";
        $countresult = $conn->query($countdata);
        $countrow = mysqli_fetch_row($countresult); 
        $total_comment = $countrow[0];
        echo "Post Title: $posttitle";
        echo "Post Comment: $total_comment";
    }
} else {
    echo "0 results";
}

上面的代碼導致：

無法獲取mysqli_fetch_row（）

Answer 1

您只需要一個查詢，將“SELECT * FROM posts”替換為

    SELECT post_title,count(posts.post_id) as Total FROM posts JOIN comments WHERE posts.post_id = comments.post_id GROUP BY posts.post_id

然后你會有

      $posttitle = $row['post_title'];
      $total_comment =$row['Total'];

      echo "Post Title: $posttitle";
      echo "Post Comment: $total_comment";

最終代碼

 $displaypost = "SELECT post_title,count(posts.post_id) as Total FROM posts JOIN comments WHERE posts.post_id = comments.post_id GROUP BY posts.post_id";
 $result = $conn->query($displaypost);

if ($result->num_rows > 0) {

while($row = $result->fetch_assoc()) {
      $posttitle = $row['post_title'];
      $total_comment =$row['Total'];

      echo "Post Title: $posttitle";
      echo "Post Comment: $total_comment";
}
} else {
echo "0 results";
}

Answer 2

您可以使用SQL Join和Gouping子句一次完成所有操作

SELECT Posts.*,Count(Comments.*) as CommentCount FROM posts Posts LEFT JOIN comments Comments ON (Post.id = Comments.post_id) GROUP BY Post.id

https://dev.mysql.com/doc/refman/5.0/en/join.html

https://dev.mysql.com/doc/refman/5.1/en/group-by-handling.html

編輯：

     $query = "SELECT Posts.*,Count(Comments.*) as CommentCount FROM posts Posts LEFT JOIN comments Comments ON (Post.id = Comments.post_id) GROUP BY Post.id";  
     $result = $conn->query($query);
     while($row = $result->fetch_assoc()) {
         echo "Post ID: {$row['id']} has {$row['CommentCount']} Comment(s)! <br />";
     }

Answer 3

在你的代碼中， WHERE post_id='$postid'";
它應該是"WHERE post_id=" + $postid +";"; 因為你沒有添加變量只是在其中創建一個帶有變量名的長字符串。