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[英]Get Username from other table by author_id from another table CakePHP
[英]CakePHP get record from another table if the id matches
我是CakePHP的新手,在我逐步解決每個問題時仍在學習。
我有兩個表:客戶和商店。 在stores表中,我有一個名為customer_id的外鍵,其中包含來自customers表的客戶ID。
在CakePHP中,我為上述表創建了控制器,模型和視圖。 從CustomerController.php中查看操作,我正在嘗試獲取與客戶ID匹配的商店。
CustomerController.php頁面:
class CustomersController extends AppController
{
public function index()
{
$customers = $this->Customers->find('all'); // Find all the records from the database.
$this->set('customers', $customers);
$stores = $this->Customers->Stores->find('all');
$this->set('stores', $stores);
}
public function view($id = NULL)
{
$customer = $this->Customers->get($id); // Find a record for individual record.
$this->set('customer', $customer);
// $stores = $this->Customers->Stores->find('all');
$stores = $this->Customers->Stores->find('list', [
'keyField' => 'id',
'valueField' => 'store_name'
]);
$this->set('store', $stores);
}
}
SQL表:
CREATE TABLE IF NOT EXISTS `customers` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`first_name` varchar(50) DEFAULT NULL,
`last_name` varchar(50) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
--
-- Dumping data for table `customers`
--
INSERT INTO `customers` (`id`, `first_name`, `last_name`) VALUES
(1, 'Ray', 'Mak'),
(2, 'John', 'Smith'),
(3, 'Mike', 'Gorge');
-- --------------------------------------------------------
--
-- Table structure for table `states`
--
CREATE TABLE IF NOT EXISTS `states` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`state_name` varchar(100) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
--
-- Dumping data for table `states`
--
INSERT INTO `states` (`id`, `state_name`) VALUES
(1, 'TX'),
(2, 'VA'),
(3, 'WI'),
(4, 'AZ'),
(5, 'FL');
-- --------------------------------------------------------
--
-- Table structure for table `stores`
--
CREATE TABLE IF NOT EXISTS `stores` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`customer_id` int(11) DEFAULT NULL,
`store_name` varchar(50) DEFAULT NULL,
`corp_name` varchar(200) DEFAULT NULL,
`street_address` varchar(200) DEFAULT NULL,
`city` varchar(50) DEFAULT NULL,
`state_id` int(11) DEFAULT NULL,
`zipcode` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `customers_idx` (`customer_id`),
KEY `states_idx` (`state_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ;
查看頁面:
<pre>
<?php
print_r(json_encode($store));
print_r(h($customer));
?>
</pre>
我可以使用帶有左聯接的自定義SQL查詢來獲取結果,但是在cakephp中,當id匹配時如何從另一個表獲取數據令人困惑。
任何幫助將不勝感激 :)
射線,
您在注釋中提到已解決了問題,但是,如果您在CustomersController :: view函數中使用以下代碼,則$ id不代表商店標識。
$stores = $this->Customers->Stores->find('all',[ 'conditions' => array('Stores.id' => $id)]);
為了獲得與客戶關聯的商店,您必須參考以下代碼
$stores = $this->Customers->Stores->findByCustomerId($id);
//where $id represents customer_id from stores table
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