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不使用Cpanel上傳數據庫

[英]Upload database without Cpanel

我已經完成了一個WordPress項目(localhost),並使用核心FTP LE上傳到Web。問題是我沒有從客戶端獲取任何cpnael詳細信息來導入我在Localhost中創建的數據庫...有什么方法可以進行?[在Google中嘗試過,但找不到合適的解決方案]我遇到了錯誤

建立數據庫連接時出錯,可能是bcaz

注意:我僅收到FTP詳細信息和數據庫詳細信息,但未獲取cPanel詳細信息

請幫我。謝謝提前。

您可以將某個PHP腳本上傳到服務器,該服務器會將數據導入到BigDump之類的數據庫中, 可以編寫自己的腳本

您可以在服務器附加文件上運行此代碼,然后在此處進行導入。

<html>
<head>
<style type="text/css">
body {
    background: #E3F4FC;
    font: normal 14px/30px Helvetica, Arial, sans-serif;
    color: #2b2b2b;
}
a {
    color:#898989;
    font-size:14px;
    font-weight:bold;
    text-decoration:none;
}
a:hover {
    color:#CC0033;
}

h1 {
    font: bold 14px Helvetica, Arial, sans-serif;
    color: #CC0033;
}
h2 {
    font: bold 14px Helvetica, Arial, sans-serif;
    color: #898989;
}
#container {
    background: #CCC;
    margin: 100px auto;
    width: 945px;
}
#form           {padding: 20px 150px;}
#form input     {margin-bottom: 20px;}
</style>
</head>
<body>
<div id="container">
<div id="form">

<?php

include "inc/database.php"; //Connect to Database

//Upload File
if (isset($_POST['submit'])) {
    if (is_uploaded_file($_FILES['filename']['tmp_name'])) {
        echo "<h1>" . "File ". $_FILES['filename']['name'] ." uploaded successfully." . "</h1>";
        echo "<h2>Displaying contents:</h2>";
        readfile($_FILES['filename']['tmp_name']);
    }

    //Import uploaded file to Database
    $handle = fopen($_FILES['filename']['tmp_name'], "r");

    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        $import="INSERT into awards (award_name, award_level, award_description, award_photo) values('$data[0]','$data[1]','$data[2]','$data[3]')";

        mysql_query($import) or die(mysql_error());
    }

    fclose($handle);

    print "Import done";

    //view upload form
}else {

    print "Upload new csv by browsing to file and clicking on Upload<br />\n";

    print "<form enctype='multipart/form-data' action='import-award.php' method='post'>";

    print "File name to import:<br />\n";

    print "<input size='50' type='file' name='filename'><br />\n";

    print "<input type='submit' name='submit' value='Upload'></form>";

}

?>

</div>
</div>
</body>
</html>

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