休眠給我無效的更新SQL查詢

Question

我嘗試使用HQL查詢：

    Session session = sessionFactory.getCurrentSession();
    Query query = session.createQuery("update AlgorithmScript set isActive = false where user.loginName=:userName");
    query.setParameter("userName", userName);
    query.executeUpdate(); 

但是Hibernate生成無效的SQL查詢：

 Hibernate: update algorithmfight_checkers_db.algorithmscripts,  set IsActive=0 where LoginName=?

幫我。

EDIT1（AlgorithmScript的實體類）：此代碼由Hibernate Tools插件生成。================================= ==================

@Entity
@Table(name = "algorithmscripts", catalog = "algorithmfight_checkers_db")
 public class AlgorithmScript implements java.io.Serializable {

private int algorithmScriptId;
private User user;
private String fileName;
private String content;
private Date uploadedDate;
private boolean isActive;
private boolean isDeleted;

public AlgorithmScript() {
}

public AlgorithmScript(int algorithmScriptId, User user, String fileName, String content, Date uploadedDate,
        boolean isActive, boolean isDeleted) {
    this.algorithmScriptId = algorithmScriptId;
    this.user = user;
    this.fileName = fileName;
    this.content = content;
    this.uploadedDate = uploadedDate;
    this.isActive = isActive;
    this.isDeleted = isDeleted;
}

@Id

@Column(name = "AlgorithmScriptId", unique = true, nullable = false)
public int getAlgorithmScriptId() {
    return this.algorithmScriptId;
}

public void setAlgorithmScriptId(int algorithmScriptId) {
    this.algorithmScriptId = algorithmScriptId;
}

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "UserId", nullable = false)
public User getUser() {
    return this.user;
}

public void setUser(User user) {
    this.user = user;
}

@Column(name = "FileName", nullable = false)
public String getFileName() {
    return this.fileName;
}

public void setFileName(String fileName) {
    this.fileName = fileName;
}

@Column(name = "Content", nullable = false, length = 65535)
public String getContent() {
    return this.content;
}

public void setContent(String content) {
    this.content = content;
}

@Temporal(TemporalType.TIMESTAMP)
@Column(name = "UploadedDate", nullable = false, length = 19)
public Date getUploadedDate() {
    return this.uploadedDate;
}

public void setUploadedDate(Date uploadedDate) {
    this.uploadedDate = uploadedDate;
}

@Column(name = "IsActive", nullable = false)
public boolean isIsActive() {
    return this.isActive;
}

public void setIsActive(boolean isActive) {
    this.isActive = isActive;
}

@Column(name = "IsDeleted", nullable = false)
public boolean isIsDeleted() {
    return this.isDeleted;
}

public void setIsDeleted(boolean isDeleted) {
    this.isDeleted = isDeleted;
}

}

Answer 1

首先，您確實需要真正意識到該查詢不是SQL查詢，而是HQL查詢。 這些語言不一樣。

以下是有關DML查詢的文檔說明：

UPDATE和DELETE語句的偽語法為：（UPDATE | DELETE）FROM？ EntityName（WHERE where_conditions）?。

需要注意的幾點：

• 在從句中，FROM關鍵字是可選的

• 從子句中只能有一個命名的實體。 但是，可以使用別名。 如果實體名稱是別名，則任何屬性引用都必須使用該別名進行限定。 如果實體名稱沒有別名，則對任何屬性引用進行限定都是非法的。

• 在批量HQL查詢中，不能指定第16.4節“隱式或顯式的連接語法形式”。 子查詢可以在where子句中使用，其中子查詢本身可能包含聯接。

• where子句也是可選的。

您的查詢是

update AlgorithmScript set isActive = false where user.loginName=:userName"

因此它違反了第三點，因為它在AlgorithmScript實體和User實體之間使用了隱式聯接。