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[英]Click event for multiple dynamically generated elements with the same class name to hide and unhide other elements
[英]How to remove multiple dynamically generated elements at the same time by their class name?
我正在做一個電子商務項目,對於運輸部分,我讓用戶輸入一個與價格相關的區域,然后用“刪除”按鈕顯示這兩個值。 用戶可以多次生成這三個元素。(並且在這三個生成的元素中的每個元素上,都有兩個隱藏的輸入以處理值,然后使用php處理該數據)單擊刪除按鈕時,我想刪除輸入的區域+價格+刪除按鈕,其相似的類別名稱。 但是,當它動態生成時該怎么辦呢? 這是HTML部分:
<label for="places">Places/area : </label>
<input type="text" name="ps_places" id="ps_places" value="" >
<label for="ps_price" "> Price : </label><input type="text" name="ps_price" id="ps_price" value="" >
<button type="button" onclick="ps_add()">OK</button>
<div id="display1"></div>
和javascript部分:
function addElement(parentId, elementTag, elementId, html) {
var p = document.getElementById(parentId);
var newElement = document.createElement(elementTag);
newElement.setAttribute('class', elementId);
newElement.innerHTML = html;
p.appendChild(newElement);
}
function ps_add()
{
var pv = document.getElementById('ps_places').value;
var prv = document.getElementById('ps_price').value;
if((pv != "") && (prv != ""))
{
ps_id++;
addElement("display1", "span", ps_id, "- ");
addElement("display1", "label", ps_id, pv);
addElement("display1", "span", ps_id, " : ");
addElement("display1", "label", ps_id, prv);
addElement("display1", "span", ps_id, " ");
addElement("display1", "button", ps_id, "Remove");
addElement("display1", "br", ps_id, "");
var input1 = document.createElement("input");
input1.setAttribute("type", "hidden");
input1.setAttribute("class", "ps_id");
input1.setAttribute("name", "ps_places[]");
input1.setAttribute("value", pv);
display1.appendChild(input1);
var input2 = document.createElement("input");
input2.setAttribute("type", "hidden");
input2.setAttribute("class", "ps_id");
input2.setAttribute("name", "ps_price[]");
input2.setAttribute("value", prv);
display1.appendChild(input2);
}
document.getElementById('ps_places').value= "";
document.getElementById('ps_price').value= "";
}
當您添加了jquery時 ,我會假設您使用jQuery。 您可以使用以下命令按其類名刪除所有元素:
$(".classname").remove();
如果是錯誤的,並且需要純JavaScript解決方案,則可以使用以下方法:
elems = document.querySelectorAll(".classname");
for (var elem in elems)
elems[elem].parentNode.removeChild(elems[elem]);
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