[英]Mixing of GROUP columns (MIN(),MAX(),COUNT(),…) with no GROUP columns is illegal if there is no GROUP BY clause
[英]MySQl Error : #1140 - Mixing of GROUP columns (MIN(),MAX(),COUNT(),…) with no GROUP columns is illegal if there is no GROUP BY clause
我有一個查詢,用於從選擇總和和列值的表中計算每列的總和。
$query = "select sum(salleryallowance),
sum(entertainmentexp),
sum(depreciation),
sum(electricity),
sum(securitygard),
sum(machinaryrepaire),
sum(totalrepairing),
sum(othermaintanaice),
sum(postal_charge),
sum(officeexp),
sum(stationary),
sum(rent_lease_thresher),
sum(rent_tractor),
sum(traivlingallowance),
sum(transportaion_cost),
sum(bank_commition),
sum(total_exp),
sum(interest_earned),
bit_farm.name as fname,
bit_regional.name as rname
from bit_income_expenditure
inner join bit_farm on bit_income_expenditure.farm_id = bit_farm.id
inner join bit_regional on bit_income_expenditure.region_id = bit_regional.id
";
$fetch = mysql_query($query);
$row = mysql_fetch_array($fetch);
// and print my output
echo $row[0]; //and so on....
當我執行此代碼時,它顯示以下錯誤:
如果沒有GROUP BY子句,則將GROUP列(MIN(),MAX(),COUNT(),...)與GROUP列混合使用是非法的
我該如何解決這個錯誤?
您的select
子句包括:
bit_farm.name as fname, bit_regional.name as rname
MySQL默認情況下會接受此設置,但是您的系統必須具有默認設置以符合ANSI。
這取決於您想要什么。 如果要為每個“農場”和“地區”使用不同的值,請添加:
group by bit_farm.name, bit_regional.name
如果需要總計,請從select
刪除這些列。
如果您使用諸如sum(),avg(),count()之類的任何函數,那么默認情況下它將對所有數據進行求和/計數/平均,但是如果您要基於其進行分類的其他任何列, count / avg,那么您必須在where子句后提及group by,因此您的查詢應為-
select sum(salleryallowance),
sum(entertainmentexp),
sum(depreciation),
sum(electricity),
sum(securitygard),
sum(machinaryrepaire),
sum(totalrepairing),
sum(othermaintanaice),
sum(postal_charge),
sum(officeexp),
sum(stationary),
sum(rent_lease_thresher),
sum(rent_tractor),
sum(traivlingallowance),
sum(transportaion_cost),
sum(bank_commition),
sum(total_exp),
sum(interest_earned),
bit_farm.name as fname,
bit_regional.name as rname
from bit_income_expenditure
inner join bit_farm on bit_income_expenditure.farm_id = bit_farm.id
inner join bit_regional on bit_income_expenditure.region_id = bit_regional.id
group by bit_farm.name,bit_regional.name;
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