[英]SQL (HUE) : Is there any way to convert 24 hrs time into 12 hrs AM / PM format with hours buckets
[英]SQL sum of different status within 24 hrs group by hours
我試圖按小時在24小時組內總結狀態。 我有訂單,訂單狀態和狀態表。
訂單表:
+---------+-------------------------+
| orderid | orderdate |
+---------+-------------------------+
| 1 | 2015-09-16 00:04:19.100 |
| 2 | 2015-09-16 00:01:19.490 |
| 3 | 2015-09-16 00:02:33.733 |
| 4 | 2015-09-16 00:03:58.800 |
| 5 | 2015-09-16 00:01:16.020 |
| 6 | 2015-09-16 00:01:16.677 |
| 7 | 2015-09-16 00:02:06.920 |
+---------+-------------------------+
訂單狀態表:
+---------+----------+
| orderid | statusid |
+---------+----------+
| 1 | 11 |
| 2 | 22 |
| 3 | 22 |
| 4 | 11 |
| 5 | 22 |
| 6 | 33 |
| 7 | 11 |
+---------+----------+
狀態表:
+----------+----------+
| statusid | status |
+----------+----------+
| 11 | PVC |
| 22 | CCC |
| 33 | WWW |
| | |
+----------+----------+
我嘗試編寫SQL,顯示24小時內狀態的計數,以便按小時分組的不同訂單:
+------+-----+-----+-----+
| Hour | PVC | CCC | WWW |
+------+-----+-----+-----+
| 1 | 0 | 2 | 1 |
| 2 | 1 | 1 | 0 |
| 3 | 1 | 0 | 0 |
| 4 | 1 | 0 | 0 |
+------+-----+-----+-----+
到目前為止這是我的SQL。 我被困在試圖得到每個訂單狀態的總和:
SELECT
DATEPART(hour, o.orderdate) AS Hour,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('PVC') AND os.orderid = o.id AND os.statusid = stat.id
)
WHEN 'PVC' THEN 1
ELSE 0
END
) AS PVC,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('WWW') AND os.orderid = o.id AND os.statusid = stat.id
)
WHEN 'CCC' THEN 1
ELSE 0
END
) AS CCC,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('CCC') AND os.orderid = o.id AND os.statusid = stat.id)
WHEN 'WWW' THEN 1
ELSE 0
END
) AS WWW
FROM orders o
WHERE o.orderdate BETWEEN DATEADD(d,-1,CURRENT_TIMESTAMP) AND CURRENT_TIMESTAMP
GROUP BY DATEPART(hour, o.orderdate)
ORDER BY DATEPART(hour, o.orderdate);
這應該讓你更接近,然后你必須轉動:
SELECT
DATEPART(HOUR,o.orderdate) AS orderDate_hour,
s.status,
COUNT(DISTINCT o.orderid) AS count_orderID
FROM
orders o INNER JOIN
orderstatus os ON
o.orderid = os.orderid INNER JOIN
status s ON
os.statusid = s.statusid
WHERE
o.orderdate >= DATEADD(d,-1,CURRENT_TIMESTAMP)
GROUP BY
DATEPART(HOUR,o.orderdate) , s.status
ORDER BY
DATEPART(HOUR,o.orderdate)
試試這個樞軸:
SELECT
*
FROM
(SELECT
DATEPART(HOUR,o.orderdate) AS orderDate_hour,
s.status,
COUNT(DISTINCT o.orderid) AS count_orderID
FROM
orders o INNER JOIN
orderstatus os ON
o.orderid = os.orderid INNER JOIN
status s ON
os.statusid = s.statusid
WHERE
o.orderdate >= DATEADD(d,-1,CURRENT_TIMESTAMP)
GROUP BY
DATEPART(HOUR,o.orderdate) , s.status) s
PIVOT ( MAX(count_orderID) FOR status IN ('pvc','ccc','www')) AS p
ORDER BY
orderDate_hour
在這里 - 我忽略了數據中的錯誤,因為如果狀態表確實有像您的示例數據中那樣的重復ID,則會失敗。
SELECT hour, sum(PVC) as PVC, sum(CCC) as CCC, sum(WWW) as WWW
from (
select datepart(hour,orderdate) as hour,
case when s.status = 'PVC' then 1 else 0 end as PVC,
case when s.status = 'CCC' then 1 else 0 end as CCC,
case when s.status = 'WWW' then 1 else 0 end as WWW
from order o
join orderstatus os on o.orderid = os.orderid
join status s on s.statusid = os.statusid
) sub
group by hour
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