如何將此 C++ 代碼轉換為 Turbo C？

Question

C++代碼：

cout << "Roots are complex and different."  << endl;
cout << "x1 = " << realPart << "+" << imaginaryPart << "i" << endl;
cout << "x2 = " << realPart << "-" << imaginaryPart << "i" << endl;

如何將其轉換為 Turbo C 之類的printf而不是cout ？

Answer 1

可能你正在尋找這個：

printf("Roots are complex and different.\n");
printf("x1 = %lf+%lfi\n",realPart,imaginaryPart);
printf("x2 = %lf-%lfi\n",realPart,imaginaryPart);

如果realPart和imaginaryPart變量的數據類型為double 。

否則在代碼中使用%f表示float ， %d表示int ， %s表示string而不是%lf 。