[英]Echo only results that match exact string (PHP)
我正在回應WP數據庫插件的結果,並且我已經設法將所有需要的結果縮小到一個帖子ID,它現在顯示與該帖子ID相關的所有url記錄。 (向下滾動此鏈接以查看結果: http : //universitycompare.com/analytics-test/ )
這是我用來回顯SQL數據庫記錄的內容:
<?php
echo "<strong>Stack Overflow Results</strong>";
echo "<br><div style='float:left; width:100%; padding:1em; background:#FFF; margin:2em 0;'>";
$lastDate = date('Y-m-d', strtotime('today - 30 days'));
$todayDate = date('Y-m-d');
$results = $wpdb->get_results( "SELECT * FROM `wp_statistics_pages` WHERE id=37 AND `date` BETWEEN '$lastDate' AND '$todayDate' ", ARRAY_A );
for($i=0;$i<count($results);$i++)
{
echo "<span id='data-point'style='float:left;clear:left;' value='";
echo $results[$i]['count'];
echo "'>";
echo get_site_url().''.$results[$i]['uri'].' (';
echo $results[$i]['count'].')</span>';
} ?>
我有許多與URL相關的結果,但不是特定的(請參閱下面的示例,了解回顯的內容)。 我想做的只是回顯與此URL匹配的結果: http : //universitycompare.com/universities/anglia-ruskin-uni/
universitycompare.com/universities/anglia-ruskin-uni/(103)universitycompare.com/universities/anglia-ruskin-uni?offset=10(1)universitycompare.com/universities/anglia-ruskin-uni/?offset=10( 1)universitycompare.com/universities/anglia-ruskin-uni(1)
上面是一個例子,我不想回應任何與所選URL完全不匹配的結果。 理想情況下,只應顯示的記錄應該是旁邊(103)的結果。 我不知道最好的方法。
我看起來像一個正則表達式,但有點不確定? 這是我需要使用的東西嗎?
編輯,(回答上面的問題,用戶得分太低,無法回答自己的問題):
<?php
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(-1);
function startsWith($haystack, $needle) {
// search backwards starting from haystack length characters from the end
return $needle === "" || strrpos($haystack, $needle, -strlen($haystack)) !== FALSE;
}
function endsWith($haystack, $needle) {
// search forward starting from end minus needle length characters
return $needle === "" || (($temp = strlen($haystack) - strlen($needle)) >= 0 && strpos($haystack, $needle, $temp) !== FALSE);
}
echo "<strong>Stack Overflow Results</strong>";
echo "<br><div style='float:left; width:100%; padding:1em; background:#FFF; margin:2em 0;'>";
$lastDate = date('Y-m-d', strtotime('today - 30 days'));
$todayDate = date('Y-m-d');
$results = $wpdb->get_results( "SELECT * FROM `wp_statistics_pages` WHERE id=37 AND `date` BETWEEN '$lastDate' AND '$todayDate' ", ARRAY_A );
for($i=0;$i<count($results);$i++)
if (endsWith(get_site_url().''.$results[$i]['uri'], 'http://universitycompare.com/universities/anglia-ruskin-uni/'))
{
echo "<span id='data-point'style='float:left;clear:left;' value='";
echo $results[$i]['count'];
echo "'>";
echo get_site_url().''.$results[$i]['uri'].' (';
echo $results[$i]['count'].')</span>';
}
?>
你可能正在尋找startsWith()。 請嘗試以下方法:
if (startsWith($results[$i]['count'], 'universitycompare.com/universities/anglia-ruskin-uni'))
{
echo "<span id='data-point'style='float:left;clear:left;' value='";
echo $results[$i]['count'];
echo "'>";
echo get_site_url().''.$results[$i]['uri'].' (';
echo $results[$i]['count'].')</span>';
}
startsWith()和endsWith()的實現可以在這里找到startswith-end -withwith-functions-in-php
function startsWith($haystack, $needle) {
// search backwards starting from haystack length characters from the end
return $needle === "" || strrpos($haystack, $needle, -strlen($haystack)) !== FALSE;
}
function endsWith($haystack, $needle) {
// search forward starting from end minus needle length characters
return $needle === "" || (($temp = strlen($haystack) - strlen($needle)) >= 0 && strpos($haystack, $needle, $temp) !== FALSE);
}
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